GGi*_*Gio 6 mysql sql case count distinct
我的查询:
COUNT(
CASE WHEN YEAR(FieldValue) = YEAR(CURDATE())
AND MONTH(FieldValue) = MONTH(CURDATE())
THEN 1
END
) AS mtd
Run Code Online (Sandbox Code Playgroud)
我想要的东西:
COUNT(
CASE WHEN YEAR(FieldValue) = YEAR(CURDATE())
AND MONTH(FieldValue) = MONTH(CURDATE())
THEN DISTINCT ColumnID
END
) AS mtd
Run Code Online (Sandbox Code Playgroud)
这给出了一个错误.我不能使用GROUP BY.如果我在CASE之前添加DISTINCT它不起作用,它将FieldValue列视为DISTINCT,但我希望它将ColumnID计为不同.
请帮忙
ech*_*_Me 21
试试这个
COUNT(DISTINCT(
CASE WHEN YEAR(FieldValue) = YEAR(CURDATE())
AND MONTH(FieldValue) = MONTH(CURDATE())
THEN ColumnID
END )
) AS mtd
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
23330 次 |
| 最近记录: |