列表解析中的Python any()函数

Question

我是Python的新手(2周!)并且正在努力解决以下问题:

我有一个URL列表,我想迭代并找到某些URL.为此,我想测试URL中存在元组的任何成员.

我已经发现我需要一个any()语句,但无法正确获取语法:

allurls = [<big list of URLs>]

words = ('bob', 'fred', 'tom')

urlsIwant = [x for x in allurls if any(w for w in words) in x]

抓住我

TypeError: 'in <string>' requires string as left operand, not bool

我不认为它是相关的,但我的实际代码是

urlsIwant = sorted(set([x for x in allurls if dict['value'] in x and any(w for w in words) in x]))

Answer 1

包括in x在any():

urlsIwant = [x for x in allurls if any(w in x for w in words)]