如何在c#中从XDocument创建缩进的XML字符串？

Question

我有一个XDocument对象,ToString()方法返回XML而没有任何缩进.如何从包含缩进的XML创建字符串？

编辑:我问的是如何创建一个内存字符串而不是写出文件.

编辑:看起来我不小心在这里问了一个技巧问题... ToString()确实返回缩进的XML.

Answer 1

XDocument doc = XDocument.Parse(xmlString);
string indented = doc.ToString();

Answer 2

从这里开始

XmlDocument doc = new XmlDocument();
doc.LoadXml("<item><name>wrench</name></item>");

// Save the document to a file and auto-indent the output.
XmlTextWriter writer = new XmlTextWriter("data.xml",null);
writer.Formatting = Formatting.Indented;
doc.Save(writer);

Answer 3

还有一种同样的汤的味道... ;-)

StringWriter sw = new StringWriter();
XmlTextWriter xw = new XmlTextWriter(sw);
xw.Formatting = Formatting.Indented;
doc.WriteTo(xw);
Console.WriteLine(sw.ToString());

编辑:感谢John Saunders.这是一个更适合在MSDN上创建XML Writer的版本.

using System;
using System.Text;
using System.Xml;
using System.Xml.Linq;

class Program
{
    static void Main(string[] args)
    {
        XDocument doc = new XDocument(
        new XComment("This is a comment"),
        new XElement("Root",
            new XElement("Child1", "data1"),
            new XElement("Child2", "data2")
            )
            );

        var builder = new StringBuilder();
        var settings = new XmlWriterSettings()
        {
            Indent = true
        };
        using (var writer = XmlWriter.Create(builder, settings))
        {
            doc.WriteTo(writer);
        }
        Console.WriteLine(builder.ToString());
    }
}

Answer 4

要使用 XDocument（而不是 XmlDocument）创建字符串，您可以使用：

        XDocument doc = new XDocument(
            new XComment("This is a comment"),
            new XElement("Root",
                new XElement("Child1", "data1"),
                new XElement("Child2", "data2")
            )
        );

        XmlWriterSettings settings = new XmlWriterSettings();
        settings.Indent = true;
        StringBuilder sb = new StringBuilder();
        using (XmlWriter writer = XmlTextWriter.Create(sb, settings)) {
            doc.WriteTo(writer);
            writer.Flush();
        }
        string outputXml = sb.ToString();

编辑：更新为使用XmlWriter.Create和StringBuilder良好的形式（using）。