如何用单个逗号替换多次出现的逗号

Question

早些时候,我有字符串 1,2,3,,5,6,7

要替换字符串,我使用了stringByReplacingOccurrencesOfString:@",," withString:@",",输出为1,2,3,5,6,7

现在我有如下字符串.

1,2,3,,,6,7

要替换字符串,我使用了stringByReplacingOccurrencesOfString:@",," withString:@",",输出为1,2,3,,6,7

有没有办法我可以用单个逗号替换所有双逗号.

我知道我可以使用for循环或while循环,但我想检查有没有其他方法？

for (int j=1;j<=100;j++) {
    stringByReplacingOccurrencesOfString:@",," withString:@","]] 
}

Answer 1

NSString *string = @"1,2,3,,,6,7";
NSError *error = nil;
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:@",{2,}" options:NSRegularExpressionCaseInsensitive error:&error];
NSString *modifiedString = [regex stringByReplacingMatchesInString:string options:0 range:NSMakeRange(0, [string length]) withTemplate:@","];
NSLog(@"%@", modifiedString);

这将匹配,字符串中存在的任何数量.这是未来的证明:)