Scala Pickling用于Json序列化和反序列化?

pat*_*rit 3 json scala jsonserializer scala-pickling scala-2.11

对于我的项目,第戎,我想知道是否可以使用Scala pickling进行JSON 序列化序列化.具体而言,我想是这样的def toJsonString(json: JSON, prettyPrint: Boolean = false): Stringdef fromJsonString(json: String): JSON.如何使用酸洗来创建这两种辅助方法?

DCK*_*ing 7

这取决于最方便您使用的方法.这些是您所拥有的选择的粗略草图:

 import scala.pickling._, json._    

 // Uses macros implicitly on Scope
 def toJSONString[A](obj: A, prettyPrint: Boolean = false)(implicit pickler: A => JSONPickle) = {
    val json = pickler(obj)
    myPrettyPrinter.print(json.value, prettyPrint)
 }

 // Uses macros defined elsewhere
 def toJSONString(obj: Any, prettyPrint: Boolean = false) = {
    val json = classToPicklerMap(obj.getClass)(obj)
    myPrettyPrinter.print(json.value, prettyPrint)
 }

 // Uses runtime reflection
 def toJSONString(obj: Any, prettyPrint: Boolean = false) = {
    val json = obj.pickle
    myPrettyPrinter.print(json.value, prettyPrint)
 }

 // Uses macros implicitly on scope
 def fromJSONString[A](json: String)(implicit unpickler: JSONPickle => A): A = {
    unpickler(JSONPickle(json))
 }

 // Uses macros defined elsewhere #1
 def fromJSONString[A](json: String)(implicit c: ClassTag[A]) = {
    classnameToUnpicklerMap(c.runtimeClass.getName)(json).asInstanceOf[A]
 }

 // Uses macros defined elsewhere #2
 def fromJSONString(json: String): Any = {
    val className = parseClassName(json) // Class name is stored in "tpe" field in the JSON    
    classnameToUnpicklerMap(className)(json)
 }

 // Uses runtime reflection
 def fromJSONString(json: String) = JSONPickler(json).unpickle
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