geocoder.getFromLocation函数抛出"超时等待服务器响应"异常

Question

我试图通过从MainActivity启动IntentService来获取用户的位置.在服务内部我尝试反转地理编码try块内的位置,但是当我捕获异常并打印它时说"超时等待服务器响应"异常.但有几次我有位置.所以我认为没有什么我的代码有问题.但如果它从10中抛出异常8次就没用了.所以你可以建议一些事情来避免这种情况.

Answer 1

http://maps.googleapis.com/maps/api/geocode/json?latlng=lat,lng&sensor=true

Geocoder有超时等待服务器响应的错误.换句话说,您可以从代码中获取此请求以获取相应lat,lng的位置地址的json响应.

Answer 2

这是一个简单且可行的解决方案：

创建以下两个函数：

public static JSONObject getLocationInfo(String address) {
    StringBuilder stringBuilder = new StringBuilder();
    try {

    address = address.replaceAll(" ","%20");    

    HttpPost httppost = new HttpPost("http://maps.google.com/maps/api/geocode/json?address=" + address + "&sensor=false");
    HttpClient client = new DefaultHttpClient();
    HttpResponse response;
    stringBuilder = new StringBuilder();


        response = client.execute(httppost);
        HttpEntity entity = response.getEntity();
        InputStream stream = entity.getContent();
        int b;
        while ((b = stream.read()) != -1) {
            stringBuilder.append((char) b);
        }
    } catch (ClientProtocolException e) {
    } catch (IOException e) {
    }

    JSONObject jsonObject = new JSONObject();
    try {
        jsonObject = new JSONObject(stringBuilder.toString());
    } catch (JSONException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

    return jsonObject;
}
private static List<Address> getAddrByWeb(JSONObject jsonObject){
    List<Address> res = new ArrayList<Address>();
    try
    {
        JSONArray array = (JSONArray) jsonObject.get("results");
        for (int i = 0; i < array.length(); i++)
        {
            Double lon = new Double(0);
            Double lat = new Double(0);
            String name = "";
            try
            {
                lon = array.getJSONObject(i).getJSONObject("geometry").getJSONObject("location").getDouble("lng");

                lat = array.getJSONObject(i).getJSONObject("geometry").getJSONObject("location").getDouble("lat");
                name = array.getJSONObject(i).getString("formatted_address");
                Address addr = new Address(Locale.getDefault());
                addr.setLatitude(lat);
                addr.setLongitude(lon);
                addr.setAddressLine(0, name != null ? name : "");
                res.add(addr);
            }
            catch (JSONException e)
            {
                e.printStackTrace();

            }
        }
    }
    catch (JSONException e)
    {
        e.printStackTrace();

    }

    return res;
}

现在只需更换

geocoder.getFromLocation(locationAddress, 1); 

和

getAddrByWeb(getLocationInfo(locationAddress));