Ste*_*fan 14 fluent-nhibernate sql-server-ce
代码失败了
session.Save(employee);Run Code Online (Sandbox Code Playgroud)使用AssertionFailure"null identifier".我究竟做错了什么?
using FluentNHibernate.Cfg;
using FluentNHibernate.Cfg.Db;
using FluentNHibernate.Mapping;
using NHibernate;
using NHibernate.Cfg;
using NHibernate.Tool.hbm2ddl;
namespace FNHTest
{
public class Employee
{
public virtual int Id
{
get;
private set;
}
public virtual string Name
{
get;
set;
}
public virtual string Surname
{
get;
set;
}
}
public class EmployeeMap : ClassMap
{
public EmployeeMap()
{
Id(e => e.Id);
Map(e => e.Name);
Map(e => e.Surname);
}
}
public class DB
{
private static ISessionFactory mySessionFactory = null;
private static ISessionFactory SessionFactory
{
get
{
if (mySessionFactory == null)
{
mySessionFactory = Fluently.Configure()
.Database(MsSqlCeConfiguration.Standard
.ConnectionString("Data Source=MyDB.sdf"))
.Mappings(m => m.FluentMappings.AddFromAssemblyOf())
.ExposeConfiguration(BuildSchema)
.BuildSessionFactory();
}
return mySessionFactory;
}
}
private static void BuildSchema(Configuration configuration)
{
SchemaExport schemaExport = new SchemaExport(configuration);
schemaExport.Execute(false, true, false);
}
public static ISession OpenSession()
{
return SessionFactory.OpenSession();
}
}
public class Program
{
public static void Main(string[] args)
{
var employee = new Employee
{
Name = "John",
Surname = "Smith"
};
using (ISession session = DB.OpenSession())
{
session.Save(employee);
}
}
}
}Run Code Online (Sandbox Code Playgroud)
Jam*_*Ide 28
将NHibernate与SQL CE标识列一起使用时会出现"错误".我知道有两种解决方法:
1 - 将connection.release_mode属性设置为on_close配置:
mySessionFactory = Fluently.Configure()
.Database(MsSqlCeConfiguration.Standard
.ConnectionString("Data Source=MyDB.sdf"))
.Mappings(m => m.FluentMappings.AddFromAssemblyOf())
.ExposeConfiguration(BuildSchema)
.ExposeConfiguration(x => x.SetProperty("connection.release_mode", "on_close"))
.BuildSessionFactory();
Run Code Online (Sandbox Code Playgroud)
2 - 在事务中执行插入:
using (ISession session = DB.OpenSession())
using (ITransaction txn = session.BeginTransaction())
{
session.Save(employee);
txn.Commit();
}
Run Code Online (Sandbox Code Playgroud)
我意识到这个问题已经超过一个月了,但我希望这个答案对你有用.
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