如何创建EditText仅在android中接受Alphabets？

Question

如何在android中的EditText中只输入字母？

Answer 1

使用EditText标记添加此行.

android:digits="abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"

您的EditText标记应如下所示:

<EditText
        android:id="@+id/editText1"
        android:digits="abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
        android:layout_width="fill_parent"
        android:layout_height="wrap_content" />

Answer 2

edittext.setFilters(new InputFilter[] {
    new InputFilter() {
        public CharSequence filter(CharSequence src, int start,
                int end, Spanned dst, int dstart, int dend) {
            if(src.equals("")){ // for backspace
                return src;
            }
            if(src.toString().matches("[a-zA-Z ]+")){
                return src;
            }
            return edittext.getText().toString();
        }
    }
});

请彻底测试!

Answer 3

EditText state = (EditText) findViewById(R.id.txtState);


                Pattern ps = Pattern.compile("^[a-zA-Z ]+$");
                Matcher ms = ps.matcher(state.getText().toString());
                boolean bs = ms.matches();
                if (bs == false) {
                    if (ErrorMessage.contains("invalid"))
                        ErrorMessage = ErrorMessage + "state,";
                    else
                        ErrorMessage = ErrorMessage + "invalid state,";

                }

Answer 4

对于那些希望他们的editText只接受字母和空格(既不是数字也不是任何特殊字符)的人,那么可以使用它InputFilter.在这里,我创建了一个名为getEditTextFilter()InputFilter并在其中编写的方法.

public static InputFilter getEditTextFilter() {
        return new InputFilter() {

            @Override
            public CharSequence filter(CharSequence source, int start, int end, Spanned dest, int dstart, int dend) {

                boolean keepOriginal = true;
                StringBuilder sb = new StringBuilder(end - start);
                for (int i = start; i < end; i++) {
                    char c = source.charAt(i);
                    if (isCharAllowed(c)) // put your condition here
                        sb.append(c);
                    else
                        keepOriginal = false;
                }
                if (keepOriginal)
                    return null;
                else {
                    if (source instanceof Spanned) {
                        SpannableString sp = new SpannableString(sb);
                        TextUtils.copySpansFrom((Spanned) source, start, sb.length(), null, sp, 0);
                        return sp;
                    } else {
                        return sb;
                    }
                }
            }

            private boolean isCharAllowed(char c) {
                Pattern ps = Pattern.compile("^[a-zA-Z ]+$");
                Matcher ms = ps.matcher(String.valueOf(c));
                return ms.matches();
            }
        };
    }

找到后将此inputFilter附加到editText,如下所示:

mEditText.setFilters(new InputFilter[]{getEditTextFilter()});

最初的功劳归功于@UMAR,他提出了使用正则表达式和@KamilSeweryn进行验证的想法

Answer 5

通过Xml,您可以轻松地在xml(editText)中输入以下代码...

android:digits="abcdefghijklmnopqrstuvwxyz"

只接受字符...

Answer 6

放入代码edittext xml文件,

   android:digits="abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"

Answer 7

对于空格，您可以在数字中添加单个空格。如果您需要任何特殊字符，例如圆点，逗号，也可以添加到此列表中

android：digits =“ abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ”

Answer 8

在EditText android中只允许使用字母:

InputFilter letterFilter = new InputFilter() {
        public CharSequence filter(CharSequence source, int start, int end, Spanned dest, int dstart, int dend) {
            String filtered = "";
            for (int i = start; i < end; i++) {
                char character = source.charAt(i);
                if (!Character.isWhitespace(character)&&Character.isLetter(character)) {
                    filtered += character;
                }
            }

            return filtered;
        }

    };
editText.setFilters(new InputFilter[]{letterFilter});