Tre*_*era 1 python dictionary list python-3.x
我想垂直打印以下列表字典:
result = {'WeightedLevel': [388.850952, 716.718689, 1312.55957, 2405.087158, 4460.083984, 8543.792969, 18805.201172, 57438.140625, 1792.367554], 'Job': 'Desktop', 'LoadLevel': [0.212399, 0.393191, 0.727874, 1.347436, 2.494368, 4.617561, 8.548006, 15.824027, 1.0], 'Task': 'test', 'Failure': [2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 2.0], 'Blocks': [7255.151855, 231.589661, 9.365415, 0.55364, 0.0504, 0.006408, 0.001204, 0.000842, 2.060041]}
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所以看起来应该是这样的:
Job Task LoadLevel Blocks Failure WeightedLevel
Desktop test 4546543 4384284 0,46544564 0,1354385
474454 978456 2 9655
9655 55654 966 665
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等等...
我尝试过在网上找到的一些代码,但它们仍然会横向打印结果:
for k, d in result.items():
print(k + ":", d)
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和
print("\t".join(str(x) for x in result))
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漂亮的打印表需要大量的代码(table-recipe,pretty-table).在特定的基础上编写这种代码并不好玩; 你不妨使用精心设计的模块.
如果你有pandas,你可以将dict直接转储到DataFrame中,然后像这样打印:
In [4]: import pandas as pd
In [5]: result = {'WeightedLevel': [388.850952, 716.718689, 1312.55957, 2405.087158, 4460.083984, 8543.792969, 18805.201172, 57438.140625, 1792.367554], 'Job': 'Desktop', 'LoadLevel': [0.212399, 0.393191, 0.727874, 1.347436, 2.494368, 4.617561, 8.548006, 15.824027, 1.0], 'Task': 'test', 'Failure': [2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 2.0], 'Blocks': [7255.151855, 231.589661, 9.365415, 0.55364, 0.0504, 0.006408, 0.001204, 0.000842, 2.060041]}
In [6]: pd.DataFrame(result)
Out[6]:
Blocks Failure Job LoadLevel Task WeightedLevel
0 7255.151855 2 Desktop 0.212399 test 388.850952
1 231.589661 2 Desktop 0.393191 test 716.718689
2 9.365415 2 Desktop 0.727874 test 1312.559570
3 0.553640 2 Desktop 1.347436 test 2405.087158
4 0.050400 2 Desktop 2.494368 test 4460.083984
5 0.006408 2 Desktop 4.617561 test 8543.792969
6 0.001204 2 Desktop 8.548006 test 18805.201172
7 0.000842 2 Desktop 15.824027 test 57438.140625
8 2.060041 2 Desktop 1.000000 test 1792.367554
[9 rows x 6 columns]
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这是一种在不使用第三方模块的情况下以类似表格式打印字典的方法:
import itertools as IT
result = {'WeightedLevel': [388.850952, 716.718689, 1312.55957, 2405.087158, 4460.083984, 8543.792969, 18805.201172, 57438.140625, 1792.367554], 'Job': 'Desktop', 'LoadLevel': [0.212399, 0.393191, 0.727874, 1.347436, 2.494368, 4.617561, 8.548006, 15.824027, 1.0], 'Task': 'test', 'Failure': [2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 2.0], 'Blocks': [7255.151855, 231.589661, 9.365415, 0.55364, 0.0504, 0.006408, 0.001204, 0.000842, 2.060041]}
matrix = zip(*[value if isinstance(value, list) else IT.repeat(value) for key,value in result.items()])
print(''.join(['{:15}'.format(key) for key in result.keys()]))
for row in matrix:
print(''.join(['{:15}'.format(str(item)) for item in row]))
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产量
Task Blocks LoadLevel Failure Job WeightedLevel
test 7255.151855 0.212399 2.0 Desktop 388.850952
test 231.589661 0.393191 2.0 Desktop 716.718689
test 9.365415 0.727874 2.0 Desktop 1312.55957
test 0.55364 1.347436 2.0 Desktop 2405.087158
test 0.0504 2.494368 2.0 Desktop 4460.083984
test 0.006408 4.617561 2.0 Desktop 8543.792969
test 0.001204 8.548006 2.0 Desktop 18805.201172
test 0.000842 15.824027 2.0 Desktop 57438.140625
test 2.060041 1.0 2.0 Desktop 1792.367554
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