定义这个通用接口以便编译的最简洁方法是什么？

Question

因为,具有相同参数但返回值不同的两个方法将无法编译.在不失去清晰度的情况下定义此界面的最佳方法是什么？

public interface IDuplexChannel<T, U>
{
    void Send(T value, int timeout = -1);
    void Send(U value, int timeout = -1);
    bool TrySend(T value, int timeout = -1);
    bool TrySend(U value, int timeout = -1);
    T Receive(int timeout = -1);
    U Receive(int timeout = -1);
    bool TryReceive(out T value, int timeout = -1);
    bool TryReceive(out U value, int timeout = -1);
}

我考虑使用params,但这会使它使用起来有点尴尬.

public interface IDuplexChannel<T, U>
{
    void Send(T value, int timeout = -1);
    void Send(U value, int timeout = -1);
    bool TrySend(T value, int timeout = -1);
    bool TrySend(U value, int timeout = -1);
    void Receive(out T value, int timeout = -1);
    void Receive(out U value, int timeout = -1);
    bool TryReceive(out T value, int timeout = -1);
    bool TryReceive(out U value, int timeout = -1);
}

通用版本,有点笨拙,但它的工作原理.

public interface IDuplexChannel<T, U>
{
    void Send(T value, int timeout = -1);
    void Send(U value, int timeout = -1);
    bool TrySend(T value, int timeout = -1);
    bool TrySend(U value, int timeout = -1);
    V Receive<V>(int timeout = -1) where V : T, U;
    bool TryReceive(out T value, int timeout = -1);
    bool TryReceive(out U value, int timeout = -1);
}

Answer 1

主要问题是您尝试同时从两端查看双工通道.数据在双工通道上双向传播,但仍有明确的终点.你在一端发送的是你在另一端收到的.

public interface IDuplexChannel<TSend, TReceive>
{
    void Send(TSend data);
    TReceive Receive();
}

也就是说,无论如何你应该使用WCF,特别是因为你使用的是.NET 4.0.

编辑:图片

        "PERSON" A                                     "PERSON" B
            O            int ----------------->            O
           -|-           <-------------- string           -|-
           / \                                            / \
IDuplexChannel<int, string>                     IDuplexChannel<string, int>