Mak*_*ako -3 c++ random events integer
对于我当前的项目,我创建了一个事件,该事件应该根据我的代码生成的随机整数而改变,唯一的问题是我似乎总是得到相同的路径.总之,我希望它发生任何事件的几率为50%.谢谢,西蒙
random1 = rand() % 1 + 0;
if (random1 == 0) {
int choice4;
cout << "Your character screams at the top of his lungs, " << endl;
cout << "this causes the dragon to immediately to bow in fear..." << endl;
cout << "It turns out dragons are very sensitive to hearing....." << endl;
system("pause");
cout << "\nIt seems the dragon is requesting you ride it!\n" << endl;
cout << "Will you ride it?\n" << endl;
cout << "1. Ride it" << endl;
cout << "2. Or Wait here." << endl;
cin >> choice4;
cin.ignore();
system("cls");
if (choice4 == 1){
Ending();
}
}
else if (random1 == 1) {
cout << "Your character screams at the top of his lungs, " << endl;
cout << "eventually your breath gives out and you die because of lack of oxygen." << endl;
system("pause");
gameover();
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到目前为止,所有其他答案都提到需要使用srand()初始化随机数生成器,这是一个有效的点,但不是你遇到的问题.
你的问题是你的程序计算随机数的模数和1,它总是等于0,因为对于任何整数n,
n % 1 == remainder of the integer division of n by 1
== n - (n / 1)
== 0
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所以,替换这个:
random1 = rand() % 1 + 0;
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有了这个:
random1 = rand() % 2;
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你会得到一些你想要的东西.我说的是"有点",因为还有其他需要考虑的问题,例如随机数生成器初始化(srand()),使用rand()而不是更精细的RNG等.