'dict'对象在django项目中没有属性'status_code'错误

Question

我在我的django项目中收到此错误,我该如何解决它.

回溯切换到复制粘贴视图

/home/vishakha/webapps/django/local/lib/python2.7/site-packages/django/core/handlers/base.py in get_response
            response = self.apply_response_fixes(request, response) ...
? Local vars
/home/vishakha/webapps/django/local/lib/python2.7/site-packages/django/core/handlers/base.py in apply_response_fixes
            response = func(request, response) ...
? Local vars
/home/vishakha/webapps/django/local/lib/python2.7/site-packages/django/http/utils.py in conditional_content_removal
    if 100 <= response.status_code < 200 or response.status_code in (204, 304): ...
? Local vars

Answer 1

看起来您没有从视图中返回HttpResponse的实例.你能粘贴代码片段吗？另外,请尝试展开突出显示的异常(它用深灰色背景着色),看看'response'变量的值是多少.

Answer 2

是的，@toudi 是对的。我处于这种情况，现在我这样做：

from django.http.response import JsonResponse

return JsonResponse({'success':False, 'errorMsg':errorMsg})

在 jQuery 中处理 json 部分时，请执行以下操作：

$.ajax({
    ...
    dataType: 'json',
    success: function(returned, status, xhr) {
        var result = returned['success']; // this will be translated into 'true' in JS, not 'True' as string
        if (result) { 
            ...
        else {
            ...
        }
    }
});