打破javascript嵌套的async.each循环,但继续主循环

Question

我有一个名为recipesArray的对象数组.

recipesArray = [  [{name = "the recipe name", url = "http://recipeurl.com"},
                   {name = "the other neame", url = "http://adifferenturl.com"},
                   {name = "another recipe", url = "http://anotherurl.com"}],

                   [{name = "the recipe name", url = "http://recipeurl.com"},
                   {name = "the other neame", url = "http://adifferenturl.com"},
                   {name = "another recipe", url = "http://anotherurl.com"}],

                   [{name = "the recipe name", url = "http://recipeurl.com"},
                   {name = "the other neame", url = "http://adifferenturl.com"},
                   {name = "another recipe", url = "http://anotherurl.com"}] ]

我想打破这个嵌套的async.each循环,但继续主async.each循环.

// main async.each
async.each(recipes, function(subArray, callback1) {
   // nested async.each
   async.each(subArray, function(theCurrentRecipe, callback2) {
      checkHREFS(theCurrentRecipe, function(thisRecipe) {
         if ('i have a conditional here') {
            // break out of this nested async.each, 
            // but continue the main async.each.
         } else {
            // continue
         }
         callback2();
      });
   }, callback1);
}, function(err) {
if (err) {
   return console.error(err);

   // success, all recipes iterated
});

Answer 1

一种方法可能是修改内部each()的最终回调,以检查具有特殊属性的Error对象,该属性指示您早期爆发并且它不是真正的错误.然后在条件内部,将具有该属性集的Error对象传递给回调.

例:

// main async.each
async.each(recipes, function(subArray, callback1) {
  // nested async.each
  async.each(subArray, function(theCurrentRecipe, callback2) {
    checkHREFS(theCurrentRecipe, function(thisRecipe) {
      if ('i have a conditional here') {
        // break out of this nested async.each, 
        // but continue the main async.each.
        var fakeErr = new Error();
        fakeErr.break = true;
        return callback2(fakeErr);
      }
      // continue
      callback2();
    });
  }, function(err) {
    if (err && err.break)
      callback1();
    else
      callback1(err);
  });
}, function(err) {
  if (err)
    return console.error(err);

  // success, all recipes iterated
});