如何用BASH中的递增数替换所有匹配？

Question

我有这样的文本文件:

AAAAAA this is some content.
This is AAAAAA some more content AAAAAA. AAAAAA
This is yet AAAAAA some more [AAAAAA] content.

我需要AAAAAA用递增的数字替换所有出现的,例如,输出看起来像这样:

1 this is some content.
This is 2 some more content 3. 4
This is yet 5 some more [6] content.

如何用递增的数字替换所有匹配？

Answer 1

这是一种方法:

$ awk '{for(x=1;x<=NF;x++)if($x~/AAAAAA/){sub(/AAAAAA/,++i)}}1' file
1 this is some content.
This is 2 some more content 3. 4
This is yet 5 some more [6] content.

Answer 2

Perl 解决方案：

perl -pe 'BEGIN{$A=1;} s/AAAAAA/$A++/ge' test.dat