加入Java 8 Collection API

Question

我有两个List<Map<String, Object>>对象.

[{Month=August-2013, Sales=282200}, {Month=July-2013, Sales=310400}, 
 {Month=June-2013, Sales=309600}, {Month=May-2013, Sales=318200}, 
 {Month=September-2013, Sales=257800}]

和

[{Month=April-2013, NoOfTranx=8600}, {Month=August-2013, NoOfTranx=6700}, 
 {Month=July-2013, NoOfTranx=14400}, {Month=June-2013, NoOfTranx=8500}, 
 {Month=May-2013, NoOfTranx=14400}]

我想把join(Merge)这两个List放在Month键上.如何FULL OUTER JOIN, RIGHT OUTER JOIN使用新的Collection在这些List上执行多个连接操作(即等)API.

Answer 1

执行完全外连接的一种方法是首先构造一个Map<String, Map<String, Object>>将月值链接到映射本身并获取列表中的值的方法:

//first concatenate the two lists
Map<String, Map<String, Object>> result = Stream.concat(list1.stream(),
                                                        list2.stream())
                //then collect in a map where the key is the value of the month
                .collect(toMap(m -> (String) m.get("Month"),
                //the value is the map itself
                               m -> m,
                //merging maps (i.e. adding the "Sales" and "NoOfTranx" infos)
                               (m1, m2) -> {m1.putAll(m2); return m1; }));

//finally put that in a list
List<Map<String, Object>> merge = new ArrayList<>(result.values());

笔记:

• 原始地图被修改 - 如果这是不合需要的,您可以new HashMap<>()在合并部分创建一个.
• 对于左/右外连接,您只能流式传输一个列表并在流中添加相关条目
• 对于内连接,您可以从列表中的一个开始,过滤元素出现在另一个列表中,并继续如上所述

以下完整示例打印:

list1 = [{Month=August-13, Sales=282200}, {Month=July-13, Sales=310400}]
list2 = [{Month=August-13, NoOfTranx=6700}, {Month=July-13, NoOfTranx=14400}]
merge = [{Month=August-13, Sales=282200, NoOfTranx=6700}, {Month=July-13, Sales=310400, NoOfTranx=14400}]

码:

public static void main(String[] args) {
    List<Map<String, Object>> list1 = new ArrayList<>();
    list1.add(map("Month", "August-13", "Sales", 282200));
    list1.add(map("Month", "July-13", "Sales", 310400));
    System.out.println("list1 = " + list1);

    List<Map<String, Object>> list2 = new ArrayList<>();
    list2.add(map("Month", "August-13", "NoOfTranx", 6700));
    list2.add(map("Month", "July-13", "NoOfTranx", 14400));
    System.out.println("list2 = " + list2);

    Map<String, Map<String, Object>> result = Stream.concat(list1.stream(),
                                                            list2.stream())
                .collect(toMap(m -> (String) m.get("Month"),
                               m -> m,
                               (m1, m2) -> {m1.putAll(m2); return m1; }));

    List<Map<String, Object>> merge = new ArrayList<>(result.values());
    System.out.println("merge = " + merge);
}

private static Map<String, Object> map(Object... kvs) {
    Map<String, Object> map = new HashMap<>();
    for (int i = 0; i < kvs.length; i += 2) {
        map.put((String) kvs[i], kvs[i+1]);
    }
    return map;
}