如何以编程方式关闭WAR/EAR

Question

有没有办法以编程方式停止WAR/EAR？

如果在启动/配置过程中出现问题,我需要停止应用程序部署.

如果可能,解决方案应该是跨服务器兼容的,因为我们的应用程序必须在JBoss AS 7和Websphere 7/8中运行.

目前,应用程序无法在JBoss上启动,它在部署期间出现未知错误,并且加载程序不会在取消部署中消失.在Websphere上,应用程序启动,尽管它从配置中启动了一些错误

看来,虽然我正在销毁我的ServerHttpServlet,但我无法销毁Jersey servlet.有关如何实现这一点的任何想法？

web.xml中

<?xml version="1.0" encoding="UTF-8"?>
<web-app id="WebApp_ID" version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
    <display-name>Server</display-name>
    <servlet>
        <description></description>
        <display-name>ServerHttpServlet</display-name>
        <servlet-name>ServerHttpServlet</servlet-name>
        <servlet-class>com.transactionservice.service.ServerHttpServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet>
        <description></description>
        <servlet-name>Jersey Servlet</servlet-name>
        <servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
        <init-param>
            <description></description>
            <param-name>javax.ws.rs.Application</param-name>
            <param-value>callers.REST_Application</param-value>
        </init-param>
        <load-on-startup>2</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>Jersey Servlet</servlet-name>
        <url-pattern>/jaxrs/*</url-pattern>     
    </servlet-mapping>

    <listener>
        <listener-class>com.transactionservice.service.ServerServletContext</listener-class>
    </listener>
</web-app>

callers.REST_Application

package callers;

import java.util.HashSet;
import java.util.Set;
import javax.ws.rs.core.Application;
import com.exictos.callers.DEBUG_CONFIG;
import com.exictos.log4j.LoggerCommon;

public class REST_Application extends Application
{
    private static final LoggerCommon logger = new LoggerCommon(REST_Application.class);

    public REST_Application()
    {
    }

    @Override
    public Set<Class<?>> getClasses()
    {
        Set<Class<?>> classes = null;
        try
        {
            // The available REST services
            classes = new HashSet<Class<?>>();

            classes.add(API_CALL_REST.class);
            classes.add(API_CALL_REST_ENC.class);
            classes.add(API_CALL_CONFIG.class);
            classes.add(API_CALL_ABOUT.class);
            classes.add(DEBUG_CONFIG.class);
        }
        catch(Exception e)
        {
            logger.error("", e);
        }

        return classes;
    }
}

com.transactionservice.service.ServerServletContext

package com.transactionservice.service;

import javax.servlet.ServletContextEvent;
import javax.servlet.ServletContextListener;

import com.exictos.exception.ApplicationLoadingException;

public class ServerServletContext implements ServletContextListener
{
    @Override
    public void contextInitialized(ServletContextEvent aServletContext)
    {
        //THIS IS JUST AS TEST EXAMPLE TO SEE IF WOULD WORK
        throw new RuntimeException(e);
    }


    @Override
    public void contextDestroyed(ServletContextEvent aServletContext)
    {
        System.out.println("------------------");
    }
}

Answer 1

查看JSR-88 - 应用程序部署。可以在此处找到WebSphere 快速入门。请注意，Wildfly删除了 JSR-88 支持。

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也可以通过货物以编程方式停止部署。

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I\xe2\x80\x99m 不太确定你想做什么，但我认为正常的方法应该是部署应用程序的人员或进程应该验证部署是否有效，如果没有，则以相同的方式取消部署。

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