将字符串拆分为Python中的列表

Question

我有一个文本文件,我想放入列表.

文本文件如下所示:

New  Distribution  Votes  Rank  Title
     0000000125  1196672  9.2  The Shawshank Redemption (1994)
     0000000125  829707   9.2  The Godfather (1972)
     0000000124  547511   9.0  The Godfather: Part II (1974)
     0000000124  1160800  8.9   The Dark Knight (2008)

我试过用这段代码拆分列表:

x = open("ratings.list.txt","r")
movread = x.readlines()
x.close()


s = raw_input('Search: ')
for ns in movread:
    if s in ns:
        print(ns.split()[0:100])

输出:

      Search: #1 Single
     ['1000000103', '56', '6.3', '"#1', 'Single"', '(2006)']

但它并没有给我我想要的输出

它分裂在标题之间的空格上.

如何在不破坏标题的情况下将其拆分为列表？

预期产量:

 Search: #1 Single

  Distribution  Votes  Rank           Title
 ['1000000103', '56', '6.3', '"#1 Single" (2006)']

Answer 1

split()采用可选maxsplit参数:

在Python 3中:

>>> s = "     0000000125  1196672  9.2  The Shawshank Redemption (1994)"
>>> s.split()
['0000000125', '1196672', '9.2', 'The', 'Shawshank', 'Redemption', '(1994)']
>>> s.split(maxsplit=3)
['0000000125', '1196672', '9.2', 'The Shawshank Redemption (1994)']

在Python 2中,您需要将maxsplit参数指定为位置参数:

>>> s = "     0000000125  1196672  9.2  The Shawshank Redemption (1994)"
>>> s.split(None, 3)
['0000000125', '1196672', '9.2', 'The Shawshank Redemption (1994)']