我有这个解决方案,我正在努力,并尝试将3个不同问题的userInput返回给Main.这就是我目前所拥有的.
public static string GetInput()
{
//declared variables
string userInput;
string outputTitle;
Console.Write("Enter your name: ");
userInput= Console.ReadLine();
Console.Write("Enter your age: ");
userInput = Console.ReadLine();
Console.Write("Enter the Gas Mileage: ");
userInput = Console.ReadLine();
return userInput;
}
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我设置它的方式我永远不会通过("输入你的名字"); 题.有什么更好的方法来解决这个问题?
userName = InputUtilities.GetInput(userName); //错误2方法'GetInput'没有重载需要1个参数
Console.Write("你的名字是:{0}",userName);
使用类来定义要捕获的输入,并返回该输入.
public class UserDetails
{
public string Name {get;set;}
public string Age {get;set;}
public string Mileage {get;set;}
}
public static UserDetails GetInput()
{
//declared variables
//string userInput;
//string outputTitle;
var userD = new UserDetails();
Console.Write("Enter your name: ");
userD.Name = Console.ReadLine();
Console.Write("Enter your age: ");
userD.Age = Console.ReadLine();
Console.Write("Enter the Gas Mileage: ");
userD.Mileage = Console.ReadLine();
return userD;
}
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编辑:使用输出参数的示例.
void Main()
{
string name, age, mileage;
GetInput(out name, out age, out mileage);
//use name, age and mileage here.
}
public static void GetInput(out string pName, out string pAge, out string pMileage)
{
Console.Write("Enter your name: ");
pName = Console.ReadLine();
Console.Write("Enter your age: ");
pAge = Console.ReadLine();
Console.Write("Enter the Gas Mileage: ");
pMileage = Console.ReadLine();
}
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