Django中的MultiValueDictKeyError

use*_*619 6 python django

我在收到请求时收到此错误,而不是在发布请求期间收到此错误.

错误:-

/ StartPage /的MultiValueDictKeyError

"Key 'username' not found in <QueryDict: {}>"
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请求方法:GET请求URL:

http://127.0.0.1:8000/StartPage/
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Django版本:1.4异常类型:MultiValueDictKeyError异常值:

"密钥'用户名'未找到"

views.py

from django.shortcuts import render_to_response
from django.views.decorators.csrf import csrf_exempt
from django.template import Context, RequestContext
@csrf_exempt
def main_page(request):
    return render_to_response('main_page.html')

@csrf_exempt
def Start_Page(request):
    if request.method == 'POST':
       print 'post', request.POST['username']
    else:
       print 'get', request.GET['username']
    variables = RequestContext(request,{'username':request.POST['username'],
           'password':request.POST['password']})
    return render_to_response('Start_Page.html',variables)
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urls.py

from polls.views import *
urlpatterns = patterns('',
    # Examples:
     url(r'^$', main_page),
     url(r'^StartPage/$', Start_Page)
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main_page.html

<html>
<head>
</head>
<body>
This is the body
<form method="post" action="/StartPage/">{% csrf_token %}
Username: <input type="text" name="username">
Password: <input type="password" name="password">
<input type="submit" value="Sign with password">
</form>
</body>
</html>
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Start_Page.html

<html>
<head>
</head>
<body>
This is the StartPage
Entered user name ==   {{username}}
Entered password  == {{password}}
</body>
</html>
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ale*_*cxe 11

当然,在获取页面时,您不会username作为GET参数传递http://127.0.0.1:8000/StartPage/.

试试这个并观察打印用户名:http://127.0.0.1:8000/StartPage?username=test.

使用get()并避免MultiValueDictKeyError错误:

request.GET.get('username', '') 
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也可以看看: