如何递归调用2个函数？

Question

我有两个功能:

let fn2 =
  if "something happend" then
    fn1

let rec fn1 =
  if "something" then
    fn2

这只是一个例子,我想要做的.有什么想法怎么做？

或者我应该将2.函数发送到1.函数作为参数？

Answer 1

你需要使用let rec ... and ...:

let rec fn1 x =
    if x = "something" then
        fn2 x
and fn2 x =
    if x = "something else" then
        fn1 x