Cli*_*lip 141 c++ text opencv image-processing bounding-box
我试图在图像中找到文本的边界框,目前正在使用这种方法:
// calculate the local variances of the grayscale image
Mat t_mean, t_mean_2;
Mat grayF;
outImg_gray.convertTo(grayF, CV_32F);
int winSize = 35;
blur(grayF, t_mean, cv::Size(winSize,winSize));
blur(grayF.mul(grayF), t_mean_2, cv::Size(winSize,winSize));
Mat varMat = t_mean_2 - t_mean.mul(t_mean);
varMat.convertTo(varMat, CV_8U);
// threshold the high variance regions
Mat varMatRegions = varMat > 100;
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给出这样的图像时:
然后,当我显示varMatRegions
我得到这个图像:
正如你所看到的那样,它将左侧的文本块与卡片的标题结合起来,对于大多数卡片而言,这种方法效果很好,但在较繁忙的卡片上它可能会导致问题.
这些轮廓连接不好的原因是它使得轮廓的边界框几乎占据了整个卡片.
任何人都可以建议一种不同的方式来查找文本以确保正确检测文本吗?
200分,谁能在这两张卡上方找到文字.
dha*_*hka 124
我在下面的程序中使用了基于渐变的方法.添加了生成的图像.请注意,我正在使用图像的缩小版本进行处理.
c ++版本
The MIT License (MIT)
Copyright (c) 2014 Dhanushka Dangampola
Permission is hereby granted, free of charge, to any person obtaining a copy
of this software and associated documentation files (the "Software"), to deal
in the Software without restriction, including without limitation the rights
to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
copies of the Software, and to permit persons to whom the Software is
furnished to do so, subject to the following conditions:
The above copyright notice and this permission notice shall be included in
all copies or substantial portions of the Software.
THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN
THE SOFTWARE.
#include "stdafx.h"
#include <opencv2/core/core.hpp>
#include <opencv2/highgui/highgui.hpp>
#include <opencv2/imgproc/imgproc.hpp>
#include <iostream>
using namespace cv;
using namespace std;
#define INPUT_FILE "1.jpg"
#define OUTPUT_FOLDER_PATH string("")
int _tmain(int argc, _TCHAR* argv[])
{
Mat large = imread(INPUT_FILE);
Mat rgb;
// downsample and use it for processing
pyrDown(large, rgb);
Mat small;
cvtColor(rgb, small, CV_BGR2GRAY);
// morphological gradient
Mat grad;
Mat morphKernel = getStructuringElement(MORPH_ELLIPSE, Size(3, 3));
morphologyEx(small, grad, MORPH_GRADIENT, morphKernel);
// binarize
Mat bw;
threshold(grad, bw, 0.0, 255.0, THRESH_BINARY | THRESH_OTSU);
// connect horizontally oriented regions
Mat connected;
morphKernel = getStructuringElement(MORPH_RECT, Size(9, 1));
morphologyEx(bw, connected, MORPH_CLOSE, morphKernel);
// find contours
Mat mask = Mat::zeros(bw.size(), CV_8UC1);
vector<vector<Point>> contours;
vector<Vec4i> hierarchy;
findContours(connected, contours, hierarchy, CV_RETR_CCOMP, CV_CHAIN_APPROX_SIMPLE, Point(0, 0));
// filter contours
for(int idx = 0; idx >= 0; idx = hierarchy[idx][0])
{
Rect rect = boundingRect(contours[idx]);
Mat maskROI(mask, rect);
maskROI = Scalar(0, 0, 0);
// fill the contour
drawContours(mask, contours, idx, Scalar(255, 255, 255), CV_FILLED);
// ratio of non-zero pixels in the filled region
double r = (double)countNonZero(maskROI)/(rect.width*rect.height);
if (r > .45 /* assume at least 45% of the area is filled if it contains text */
&&
(rect.height > 8 && rect.width > 8) /* constraints on region size */
/* these two conditions alone are not very robust. better to use something
like the number of significant peaks in a horizontal projection as a third condition */
)
{
rectangle(rgb, rect, Scalar(0, 255, 0), 2);
}
}
imwrite(OUTPUT_FOLDER_PATH + string("rgb.jpg"), rgb);
return 0;
}
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python版本
The MIT License (MIT)
Copyright (c) 2017 Dhanushka Dangampola
Permission is hereby granted, free of charge, to any person obtaining a copy
of this software and associated documentation files (the "Software"), to deal
in the Software without restriction, including without limitation the rights
to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
copies of the Software, and to permit persons to whom the Software is
furnished to do so, subject to the following conditions:
The above copyright notice and this permission notice shall be included in
all copies or substantial portions of the Software.
THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN
THE SOFTWARE.
import cv2
import numpy as np
large = cv2.imread('1.jpg')
rgb = cv2.pyrDown(large)
small = cv2.cvtColor(rgb, cv2.COLOR_BGR2GRAY)
kernel = cv2.getStructuringElement(cv2.MORPH_ELLIPSE, (3, 3))
grad = cv2.morphologyEx(small, cv2.MORPH_GRADIENT, kernel)
_, bw = cv2.threshold(grad, 0.0, 255.0, cv2.THRESH_BINARY | cv2.THRESH_OTSU)
kernel = cv2.getStructuringElement(cv2.MORPH_RECT, (9, 1))
connected = cv2.morphologyEx(bw, cv2.MORPH_CLOSE, kernel)
# using RETR_EXTERNAL instead of RETR_CCOMP
contours, hierarchy = cv2.findContours(connected.copy(), cv2.RETR_EXTERNAL, cv2.CHAIN_APPROX_NONE)
#For opencv 3+ comment the previous line and uncomment the following line
#_, contours, hierarchy = cv2.findContours(connected.copy(), cv2.RETR_EXTERNAL, cv2.CHAIN_APPROX_NONE)
mask = np.zeros(bw.shape, dtype=np.uint8)
for idx in range(len(contours)):
x, y, w, h = cv2.boundingRect(contours[idx])
mask[y:y+h, x:x+w] = 0
cv2.drawContours(mask, contours, idx, (255, 255, 255), -1)
r = float(cv2.countNonZero(mask[y:y+h, x:x+w])) / (w * h)
if r > 0.45 and w > 8 and h > 8:
cv2.rectangle(rgb, (x, y), (x+w-1, y+h-1), (0, 255, 0), 2)
cv2.imshow('rects', rgb)
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Lov*_*ill 122
您可以通过查找近边元素(灵感来自LPD)来检测文本:
#include "opencv2/opencv.hpp"
std::vector<cv::Rect> detectLetters(cv::Mat img)
{
std::vector<cv::Rect> boundRect;
cv::Mat img_gray, img_sobel, img_threshold, element;
cvtColor(img, img_gray, CV_BGR2GRAY);
cv::Sobel(img_gray, img_sobel, CV_8U, 1, 0, 3, 1, 0, cv::BORDER_DEFAULT);
cv::threshold(img_sobel, img_threshold, 0, 255, CV_THRESH_OTSU+CV_THRESH_BINARY);
element = getStructuringElement(cv::MORPH_RECT, cv::Size(17, 3) );
cv::morphologyEx(img_threshold, img_threshold, CV_MOP_CLOSE, element); //Does the trick
std::vector< std::vector< cv::Point> > contours;
cv::findContours(img_threshold, contours, 0, 1);
std::vector<std::vector<cv::Point> > contours_poly( contours.size() );
for( int i = 0; i < contours.size(); i++ )
if (contours[i].size()>100)
{
cv::approxPolyDP( cv::Mat(contours[i]), contours_poly[i], 3, true );
cv::Rect appRect( boundingRect( cv::Mat(contours_poly[i]) ));
if (appRect.width>appRect.height)
boundRect.push_back(appRect);
}
return boundRect;
}
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用法:
int main(int argc,char** argv)
{
//Read
cv::Mat img1=cv::imread("side_1.jpg");
cv::Mat img2=cv::imread("side_2.jpg");
//Detect
std::vector<cv::Rect> letterBBoxes1=detectLetters(img1);
std::vector<cv::Rect> letterBBoxes2=detectLetters(img2);
//Display
for(int i=0; i< letterBBoxes1.size(); i++)
cv::rectangle(img1,letterBBoxes1[i],cv::Scalar(0,255,0),3,8,0);
cv::imwrite( "imgOut1.jpg", img1);
for(int i=0; i< letterBBoxes2.size(); i++)
cv::rectangle(img2,letterBBoxes2[i],cv::Scalar(0,255,0),3,8,0);
cv::imwrite( "imgOut2.jpg", img2);
return 0;
}
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结果:
一个.element = getStructuringElement(cv :: MORPH_RECT,cv :: Size(17,3));
湾 element = getStructuringElement(cv :: MORPH_RECT,cv :: Size(30,30));
对于所提到的其他图像,结果类似.
ana*_*ana 46
这是我用来检测文本块的另一种方法:
下面是使用pyopencv在python中编写的代码,它应该很容易移植到C++.
import cv2
image = cv2.imread("card.png")
gray = cv2.cvtColor(image,cv2.COLOR_BGR2GRAY) # grayscale
_,thresh = cv2.threshold(gray,150,255,cv2.THRESH_BINARY_INV) # threshold
kernel = cv2.getStructuringElement(cv2.MORPH_CROSS,(3,3))
dilated = cv2.dilate(thresh,kernel,iterations = 13) # dilate
_, contours, hierarchy = cv2.findContours(dilated,cv2.RETR_EXTERNAL,cv2.CHAIN_APPROX_NONE) # get contours
# for each contour found, draw a rectangle around it on original image
for contour in contours:
# get rectangle bounding contour
[x,y,w,h] = cv2.boundingRect(contour)
# discard areas that are too large
if h>300 and w>300:
continue
# discard areas that are too small
if h<40 or w<40:
continue
# draw rectangle around contour on original image
cv2.rectangle(image,(x,y),(x+w,y+h),(255,0,255),2)
# write original image with added contours to disk
cv2.imwrite("contoured.jpg", image)
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原始图片是您帖子中的第一张图片.
在预处理(灰度,阈值和扩展 - 所以在第3步之后)后,图像看起来像这样:
下面是结果图像(最后一行中的"contoured.jpg"); 图像中对象的最终边界框如下所示:
您可以看到左侧的文本块被检测为一个单独的块,与周围环境分隔.
使用具有相同参数的相同脚本(除了为第二个图像更改的阈值类型,如下所述),以下是其他2张卡的结果:
参数(阈值,扩张参数)针对该图像和该任务(查找文本块)进行了优化,并且如果需要,可以针对其他卡片图像或要找到的其他类型的对象进行调整.
对于阈值处理(步骤2),我使用黑色阈值.对于文本比背景浅的图像(例如帖子中的第二个图像),应使用白色阈值,因此请使用以下方法替换剪贴类型cv2.THRESH_BINARY
.对于第二个图像,我还使用略高的阈值值(180).改变阈值的参数和扩张的迭代次数将导致在限定图像中的对象时的不同灵敏度.
查找其他对象类型:
例如,在第一张图像中将膨胀减少到5次迭代,可以让我们对图像中的对象进行更精细的定界,粗略地找到图像中的所有单词(而不是文本块):
知道一个单词的粗略大小,在这里我丢弃了太小(宽度或高度低于20像素)或太大(超过100像素宽度或高度)的区域,以忽略不太可能是单词的对象,以获得结果上面的图片.
rtk*_*eta 26
@dhanushka的方法显示了最大的希望,但我想在Python中玩游戏,所以继续并将它翻译为有趣的:
import cv2
import numpy as np
from cv2 import boundingRect, countNonZero, cvtColor, drawContours, findContours, getStructuringElement, imread, morphologyEx, pyrDown, rectangle, threshold
large = imread(image_path)
# downsample and use it for processing
rgb = pyrDown(large)
# apply grayscale
small = cvtColor(rgb, cv2.COLOR_BGR2GRAY)
# morphological gradient
morph_kernel = getStructuringElement(cv2.MORPH_ELLIPSE, (3, 3))
grad = morphologyEx(small, cv2.MORPH_GRADIENT, morph_kernel)
# binarize
_, bw = threshold(src=grad, thresh=0, maxval=255, type=cv2.THRESH_BINARY+cv2.THRESH_OTSU)
morph_kernel = getStructuringElement(cv2.MORPH_RECT, (9, 1))
# connect horizontally oriented regions
connected = morphologyEx(bw, cv2.MORPH_CLOSE, morph_kernel)
mask = np.zeros(bw.shape, np.uint8)
# find contours
im2, contours, hierarchy = findContours(connected, cv2.RETR_CCOMP, cv2.CHAIN_APPROX_SIMPLE)
# filter contours
for idx in range(0, len(hierarchy[0])):
rect = x, y, rect_width, rect_height = boundingRect(contours[idx])
# fill the contour
mask = drawContours(mask, contours, idx, (255, 255, 2555), cv2.FILLED)
# ratio of non-zero pixels in the filled region
r = float(countNonZero(mask)) / (rect_width * rect_height)
if r > 0.45 and rect_height > 8 and rect_width > 8:
rgb = rectangle(rgb, (x, y+rect_height), (x+rect_width, y), (0,255,0),3)
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现在显示图像:
from PIL import Image
Image.fromarray(rgb).show()
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不是最恐怖的剧本,但我试图尽可能地与原始的C++代码相似,以供读者遵循.
它的工作原理几乎和原版一样好.我很乐意阅读建议如何改进/修复它以完全类似于原始结果.
以上代码JAVA版本:谢谢@William
public static List<Rect> detectLetters(Mat img){
List<Rect> boundRect=new ArrayList<>();
Mat img_gray =new Mat(), img_sobel=new Mat(), img_threshold=new Mat(), element=new Mat();
Imgproc.cvtColor(img, img_gray, Imgproc.COLOR_RGB2GRAY);
Imgproc.Sobel(img_gray, img_sobel, CvType.CV_8U, 1, 0, 3, 1, 0, Core.BORDER_DEFAULT);
//at src, Mat dst, double thresh, double maxval, int type
Imgproc.threshold(img_sobel, img_threshold, 0, 255, 8);
element=Imgproc.getStructuringElement(Imgproc.MORPH_RECT, new Size(15,5));
Imgproc.morphologyEx(img_threshold, img_threshold, Imgproc.MORPH_CLOSE, element);
List<MatOfPoint> contours = new ArrayList<MatOfPoint>();
Mat hierarchy = new Mat();
Imgproc.findContours(img_threshold, contours,hierarchy, 0, 1);
List<MatOfPoint> contours_poly = new ArrayList<MatOfPoint>(contours.size());
for( int i = 0; i < contours.size(); i++ ){
MatOfPoint2f mMOP2f1=new MatOfPoint2f();
MatOfPoint2f mMOP2f2=new MatOfPoint2f();
contours.get(i).convertTo(mMOP2f1, CvType.CV_32FC2);
Imgproc.approxPolyDP(mMOP2f1, mMOP2f2, 2, true);
mMOP2f2.convertTo(contours.get(i), CvType.CV_32S);
Rect appRect = Imgproc.boundingRect(contours.get(i));
if (appRect.width>appRect.height) {
boundRect.add(appRect);
}
}
return boundRect;
}
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并在实践中使用此代码:
System.loadLibrary(Core.NATIVE_LIBRARY_NAME);
Mat img1=Imgcodecs.imread("abc.png");
List<Rect> letterBBoxes1=Utils.detectLetters(img1);
for(int i=0; i< letterBBoxes1.size(); i++)
Imgproc.rectangle(img1,letterBBoxes1.get(i).br(), letterBBoxes1.get(i).tl(),new Scalar(0,255,0),3,8,0);
Imgcodecs.imwrite("abc1.png", img1);
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