变换使得3D卡的背面不可点击

Question

我想像http://desandro.github.io/3dtransforms/examples/card-01.html那样翻转

但每边都有按钮.所以这是我的HTML

<div class="flip-container">
    <div class="flip">
        <div class="side front">
            <p>front</p>
            <button class="front-flip-button">flip</button>
        </div>
        <div class="side back">
            <p>back</p>
            <button class="back-flip-button">flip</button>
        </div>
    </div>
</div>

和css

.flip-container{
    position: relative;
    -webkit-perspective: 800;
    width: 500px;
    height: 300px;
}
.flip{
    position: absolute;
    width: inherit;
    height: inherit;
    -webkit-transform-style: preserve-3d;
    -webkit-transition-duration: 500ms;
    -webkit-transform: translate3d(0, 0, 0);
    border: 1px solid;
}
.side{
    position: absolute;
    width: inherit;
    height: inherit;
    -webkit-transform-style: preserve-3d;
    -webkit-backface-visibility: hidden;
}
.flip.flipped,
.back{
    -webkit-transform: rotate3d(0, 1, 0, 180deg);
}
.back-flip-button,
.front-flip-button{
    position: absolute;
    left: 0;
    top: 0;
}
p{
    font-size: 90px;
    text-align: center;
}

一切都很好,但是当我使用一些元素时translateZ,后退按钮不可点击.

<div class="flip-container">
    <div class="flip">
        <div class="side front">
            <p>front</p>
            <button class="front-flip-button">flip</button>
        </div>
        <div class="side back">
            <p>back</p>
            <button class="back-flip-button">flip</button>
        </div>
    </div>
</div>

<div class="some"></div>

为什么会这样？

http://jsfiddle.net/j5Sm4/

Answer 1

应用此

.back-flip-button {
    ... Your other styles ...
    -webkit-transform:translateZ(1px);
    -webkit-backface-visibility:hidden;
    /* Needs other prefixes to be cross browser */
}

演示

这是因为父元素有自己的堆叠顺序.为了均衡堆叠顺序并将按钮置于顶部,您必须给它一个我使用过的堆叠顺序translateZ.将backface-visibility:hidden使得按钮不会显示在正面

将来我们可以通过将该will-change属性应用于背面来实现此目的