Jon*_*han 8 php doctrine symfony
我将一组实体发布到控制器,我想删除所有这些实体.但是,以下代码会引发A detached entity was found during removed MyProject\Bundle\MyBundle\Entity\MyEntity@000000004249c13f00000001720a4b59错误.我哪里错了?
$doctrineManager = $this->getDoctrine()->getManager();
foreach ($form->getData()->getEntities() as $entity) {
$doctrineManager->merge($entity);
$doctrineManager->remove($entity);
}
$doctrineManager->flush();
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小智 26
您应该对处于分离状态的实体使用合并操作,并且您希望将它们置于托管状态.
合并应该这样做$entity = $em->merge($detachedEntity).之后$entity引用合并操作返回的完全托管副本.因此,如果您$form包含分离的实体,则应调整代码,如下所示:
$doctrineManager = $this->getDoctrine()->getManager();
foreach ($form->getData()->getEntities() as $detachedEntity) {
$entity = $doctrineManager->merge($detachedEntity);
$doctrineManager->remove($entity);
}
$doctrineManager->flush();
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但是,如果$form不包含分离的实体,则应删除合并操作,如下所示:
$doctrineManager = $this->getDoctrine()->getManager();
foreach ($form->getData()->getEntities() as $entity) {
$doctrineManager->remove($entity);
}
$doctrineManager->flush();
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此图像应该可以帮助您了解实体状态转换.它取自Java Persistence API,但在Doctrine2中它大致相同.

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