使用Monit监视python程序

Question

我正在使用Monit来监控系统.我有一个我想要监视的python文件,我知道我需要创建一个包装脚本,因为python不会生成pid文件.我按照本网站上的说明操作,但是我无法启动脚本.我之前从未创建过包装器脚本,所以我认为我的脚本中有错误.来自monit的日志说"启动失败"

Monit规则

check process scraper with pidfile /var/run/scraper.pid
   start = "/bin/scraper start"
   stop = "/bin/scraper stop"

包装脚本

#!/bin/bash

PIDFILE=/var/run/scraper.pid

case $1 in
   start)
      echo $$ > ${PIDFILE};
      source /home
      exec python /home/scraper.py 2>/dev/null
   ;;
   stop)
      kill `cat ${PIDFILE}` ;;
   *)
      echo "usage: scraper {start|stop}" ;;
esac
exit 0

Answer 1

使用exec将用exec'd程序替换shell ,这不是你想要的,你希望你的包装器脚本启动程序并在返回之前将其分离,将其PID写入文件以便以后可以停止.

这是一个固定版本:

#!/bin/bash

PIDFILE=/var/run/scraper.pid

case $1 in
   start)
       source /home
       # Launch your program as a detached process
       python /home/scraper.py 2>/dev/null &
       # Get its PID and store it
       echo $! > ${PIDFILE} 
   ;;
   stop)
      kill `cat ${PIDFILE}`
      # Now that it's killed, don't forget to remove the PID file
      rm ${PIDFILE}
   ;;
   *)
      echo "usage: scraper {start|stop}" ;;
esac
exit 0