WebAPI OData验证未返回ModelState对象失败

Question

我正在创建一个AngularJS Web表单,使用WebAPI设置作为OData对表执行POST(插入).我试图返回一个失败的验证ModelState对象(以JSON格式)以验证表单上的相应字段.

我得到的所有内容都是一个字符串,所有细节都以字符串形式显示(不是JSON可解析格式)

{
  "odata.error":{
    "code":"","message":{
      "lang":"en-US","value":"The request is invalid."
    },"innererror":{
      "message":"application.ApplicationName : The ApplicationName field is required.\r\n","type":"","stacktrace":""
    }
  }
}

我的post方法如下所示:

 public async Task<IHttpActionResult> Post(Application application)
        {
           if (!ModelState.IsValid)
            {
                return BadRequest(ModelState);
            }

            db.Applications.Add(application);
            await db.SaveChangesAsync();

            return Created(application);
        }

我甚至尝试将其抽象为ActionFilterAttribute,但结果仍然相同

public class ValidateModelAttribute : ActionFilterAttribute
    {
        public override void OnActionExecuting(System.Web.Http.Controllers.HttpActionContext actionContext)
        {
            if (actionContext.ModelState.IsValid == false)
            {

                var modelState = actionContext.ModelState;

                if (!modelState.IsValid)
                    actionContext.Response = actionContext.Request
                         .CreateErrorResponse(HttpStatusCode.BadRequest, modelState);

            }
        }
    }

我的WebApi start方法具有以下配置:

public static class WebApiConfig
    {
        public static void Register(HttpConfiguration config)
        {

            config.Routes.MapHttpRoute(
               name: "DefaultApi",
               routeTemplate: "api/{controller}/{id}",
               defaults: new { id = RouteParameter.Optional }
            );

            ODataConventionModelBuilder builder = new ODataConventionModelBuilder();
            builder.EntitySet<Application>("DataApplications");
            config.Routes.MapODataRoute("odata", "odata", builder.GetEdmModel());


            config.Formatters.JsonFormatter.SerializerSettings = new JsonSerializerSettings() { NullValueHandling = NullValueHandling.Include };

            Configure(config);

            config.EnableQuerySupport();

            // Use camel case for JSON data.
            config.Formatters.JsonFormatter.SerializerSettings.ContractResolver = new CamelCasePropertyNamesContractResolver();

这是我想要实现的(与我上面的例子不匹配):

{
    "Message": "The request is invalid.",
    "ModelState": { 
        "car": [
            "Required property 'Make' not found in JSON. Path '', line 1, position 57."
        ],
        "car.Make" : [
            "The Make field is required."
        ], 
        "car.Price": [
            "The field Price must be between 0 and 200000."
        ]
    }
}

我需要返回ModelState,以便在相应的字段中定位验证反馈.

我可以检查/改变什么想法让它按照需要工作？

谢谢.

更新1 - 在asp.net上找到的参考

http://www.asp.net/aspnet/overview/aspnet-and-visual-studio-2012/aspnet-and-web-tools-20122-release-notes

OData错误响应不包含模型状态错误

使用CreateErrorResponse扩展方法或HttpErrors直接创建错误响应时,错误将映射到OData错误响应.错误响应中的任何模型状态错误都不会传播到OData错误响应.要保留OData错误响应中的模型状态错误,请直接使用CreateODataErrorResponse扩展方法或ODataError,并将模型状态错误的描述添加到OData错误消息中.

Answer 1

OData 用作ODataError错误响应。ODataError和 之间的区别HttpEror在于 HttpError 派生自Dictionary<string, object>，因此当它实例化 时ModelStateDictionary，所有模型错误都会设置为ModelState属性。但是，当您请求 OData 时，HttpError对象会映射到属性ODataError，并且所有验证错误都会连接到InnterError属性中。