Mar*_*460 4 regex string ms-access vba
所以它是9999999或所需的Medicaid格式化字符串返回值True.
样品:
AZ12345Z
NP54321J
EM17345P
到目前为止,我有2个功能一起工作,但我弄乱了逻辑!!
谢谢
Public Function isAlpha(cChar As Integer) As Boolean
'returns true if its a alphabetic character
isAlpha = IIf((cChar >= 65 And cChar <= 90) Or (cChar >= 97 And cChar <= 122), True, False)
End Function
Public Function CheckMedicaidIDFormat(strMedicaidID As String) As Boolean
Dim blnResult As Boolean
If strMedicaidID = "99999999" or If Len(strMedicaidID) = 8 And isAlpha(Left(strMedicaidID, 2)) = True And IsNumeric(Mid(strMedicaidID, 3, 5)) = True And isAlpha(Right(strMedicaidID, 1)) = True Then
blnResult = True
Else
blnResult = False
End If
CheckMecicaidIDFormat = blnResult
End Function
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虽然RegEx对于这类问题是一个很好的通用解决方案,但在这种情况下,可以进行简单的Like比较
Function IsValid(strIn As String) As Boolean
IsValid = (strIn Like "[A-Z][A-Z]#####[A-Z]") Or strIn = "99999999"
End Function
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