bry*_*bee 9 java mysql prepared-statement
我最近遇到了Java PreparedStatements的这个问题.我有以下代码:
String selectSql1
= "SELECT `value` FROM `sampling_numbers` WHERE `value` < (?)" ;
ResultSet rs1 = con.select1(selectSql1,randNum);
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select1方法在哪里
public ResultSet select1(String sql, int randNum) {
try {
this.stmt = con.prepareStatement(sql);
stmt.setInt(1, randNum);
return this.stmt.executeQuery(sql);
} catch (SQLException e) {
e.printStackTrace();
return null;
}
}
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但是,它不断抛出此错误:
com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '?)' at line 1
at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
at sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:39)
at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:27)
at java.lang.reflect.Constructor.newInstance(Constructor.java:513)
at com.mysql.jdbc.Util.handleNewInstance(Util.java:411)
at com.mysql.jdbc.Util.getInstance(Util.java:386)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1054)
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:4237)
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:4169)
at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:2617)
at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2778)
at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2828)
at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2777)
at com.mysql.jdbc.StatementImpl.executeQuery(StatementImpl.java:1651)
at util.P_DBCon.select1(P_DBCon.java:59)
at app.RandomNumberGenerator.main(RandomNumberGenerator.java:60)
Exception in thread "main" java.lang.NullPointerException
at app.RandomNumberGenerator.main(RandomNumberGenerator.java:64)
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当我做天真的做法时,这个问题不会发生......" value < " + randNum但我想这样做.
任何帮助深表感谢.
我尝试了社区的各种建议,比如
String selectSql1
= "SELECT `value` FROM `sampling_numbers` WHERE value < ?" ;
String selectSql1
= "SELECT value FROM sampling_numbers WHERE value < ?" ;
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仍然出现错误消息.
Ell*_*sch 18
您的问题的解决方案实际上非常简单,当您要调用PreparedStatement.executeQuery()时,您正在调用Statement.executeQuery(String ) -
this.stmt = con.prepareStatement(sql); // Prepares the Statement.
stmt.setInt(1, randNum); // Binds the parameter.
// return this.stmt.executeQuery(sql); // calls Statement#executeQuery
return this.stmt.executeQuery(); // calls your set-up PreparedStatement
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