Rah*_*ani 8 optimization performance jpa eclipselink
摘要:
我试图最小化我的基于JPA的Java应用程序对数据库的查询数量.我指定了@BatchFetch(BatchFetchType.IN)
优化提示,但我仍然看到一些额外的查询,我认为这些查询是多余的和不必要的.
细节:
考虑一个简单的域模型:我们有Invoice mgmt系统.发票与订单具有OneToOne关系.我们也有客户,与订单有OneToMany关系.(客户1-> M订单1 <-1发票).在此处查找更多详情.在这里找到完整的源代码.这是实体定义,因为它目前是:
Client.java(不包括getter和setter):
@Entity(name = "CUSTOMER")
public class Customer {
@Id //signifies the primary key
@Column(name = "CUST_ID", nullable = false)
@GeneratedValue(strategy = GenerationType.AUTO)
private long custId;
@Column(name = "FIRST_NAME", length = 50)
private String firstName;
@OneToMany(mappedBy="customer",targetEntity=Order.class,
fetch=FetchType.LAZY)
private Collection<Order> orders;
}
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Order.java(不包括getter和setter):
@Entity(name = "ORDERS")
public class Order {
@Id
@Column(name = "ORDER_ID", nullable = false)
@GeneratedValue(strategy = GenerationType.AUTO)
private long orderId;
@Column(name = "TOTAL_PRICE", precision = 2)
private double totPrice;
@OneToOne(fetch = FetchType.LAZY, optional = false, cascade = CascadeType.ALL, mappedBy = "order")
private Invoice invoice;
@ManyToOne(optional = false)
@JoinColumn(name = "CUST_ID", referencedColumnName = "CUST_ID")
private Customer customer;
@ManyToMany(fetch = FetchType.LAZY)
@JoinTable(name = "ORDER_DETAIL", joinColumns = @JoinColumn(name = "ORDER_ID", referencedColumnName = "ORDER_ID"), inverseJoinColumns = @JoinColumn(name = "PROD_ID", referencedColumnName = "PROD_ID"))
private List<Product> productList;
}
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Invoice.java(不包括getter和setter):
@Entity(name = "ORDER_INVOICE")
public class Invoice {
@Id
// signifies the primary key
@Column(name = "INVOICE_ID", nullable = false)
@GeneratedValue(strategy = GenerationType.AUTO)
private long invoiceId;
@Column(name = "AMOUNT_DUE", precision = 2)
private double amountDue;
@OneToOne(optional = false, fetch = FetchType.LAZY)
@JoinColumn(name = "ORDER_ID")
private Order order;
}
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有了这个模型,我运行了一个简单的测试来获取客户的所有订单.
EntityManagerFactory entityManagerFactory = Persistence.createEntityManagerFactory("testjpa");
EntityManager em = entityManagerFactory.createEntityManager();
Customer customer = em.find(Customer.class, 100L);
Collection<Order> orders = customer.getOrders();
for(Order order: orders){
System.out.println(order.getInvoice().getInvoiceId());
}
em.close();
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由于所有内容都是懒惰的,我们得到了四个查询,如下所示:
1398882535950|1|1|statement|SELECT CUST_ID, APPT, CITY, EMAIL, FIRST_NAME, LAST_NAME, STREET, LAST_UPDATED_TIME, ZIP_CODE FROM CUSTOMER WHERE (CUST_ID = ?)|SELECT CUST_ID, APPT, CITY, EMAIL, FIRST_NAME, LAST_NAME, STREET, LAST_UPDATED_TIME, ZIP_CODE FROM CUSTOMER WHERE (CUST_ID = 100)
1398882535981|0|1|statement|SELECT ORDER_ID, OREDER_DESC, ORDER_DATE, TOTAL_PRICE, LAST_UPDATED_TIME, CUST_ID FROM ORDERS WHERE (CUST_ID = ?)|SELECT ORDER_ID, OREDER_DESC, ORDER_DATE, TOTAL_PRICE, LAST_UPDATED_TIME, CUST_ID FROM ORDERS WHERE (CUST_ID = 100)
1398882535995|1|1|statement|SELECT INVOICE_ID, AMOUNT_DUE, DATE_CANCELLED, DATE_RAISED, DATE_SETTLED, LAST_UPDATED_TIME, ORDER_ID FROM ORDER_INVOICE WHERE (ORDER_ID = ?)|SELECT INVOICE_ID, AMOUNT_DUE, DATE_CANCELLED, DATE_RAISED, DATE_SETTLED, LAST_UPDATED_TIME, ORDER_ID FROM ORDER_INVOICE WHERE (ORDER_ID = 111)
1398882536004|0|1|statement|SELECT INVOICE_ID, AMOUNT_DUE, DATE_CANCELLED, DATE_RAISED, DATE_SETTLED, LAST_UPDATED_TIME, ORDER_ID FROM ORDER_INVOICE WHERE (ORDER_ID = ?)|SELECT INVOICE_ID, AMOUNT_DUE, DATE_CANCELLED, DATE_RAISED, DATE_SETTLED, LAST_UPDATED_TIME, ORDER_ID FROM ORDER_INVOICE WHERE (ORDER_ID = 222)
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由于我不希望N + 1调用获取发票,因此我考虑使用批量提取并将总查询减少到4(一个查询以获取所有客户订单的发票).为了做到这一点,我更新了我的Order实体,如下所示:
更新 - Order.java,为Invoice添加BatchFetch.(不包括吸气剂和二传手):
@Entity(name = "ORDERS")
public class Order {
@Id
@Column(name = "ORDER_ID", nullable = false)
@GeneratedValue(strategy = GenerationType.AUTO)
private long orderId;
@Column(name = "TOTAL_PRICE", precision = 2)
private double totPrice;
@BatchFetch(BatchFetchType.IN)
@OneToOne(fetch = FetchType.LAZY, optional = false, cascade = CascadeType.ALL, mappedBy = "order")
private Invoice invoice;
@ManyToOne(optional = false)
@JoinColumn(name = "CUST_ID", referencedColumnName = "CUST_ID")
private Customer customer;
@ManyToMany(fetch = FetchType.LAZY)
@JoinTable(name = "ORDER_DETAIL", joinColumns = @JoinColumn(name = "ORDER_ID", referencedColumnName = "ORDER_ID"), inverseJoinColumns = @JoinColumn(name = "PROD_ID", referencedColumnName = "PROD_ID"))
private List<Product> productList;
}
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我再次运行相同的测试,并假设将有3个查询来获取数据.(一个用于客户,一个用于订单,一个用于批量获取发票).但是,eclipselink会为此生成5个查询.以下是查询:
1398883197009|1|1|statement|SELECT CUST_ID, APPT, CITY, EMAIL, FIRST_NAME, LAST_NAME, STREET, LAST_UPDATED_TIME, ZIP_CODE FROM CUSTOMER WHERE (CUST_ID = ?)|SELECT CUST_ID, APPT, CITY, EMAIL, FIRST_NAME, LAST_NAME, STREET, LAST_UPDATED_TIME, ZIP_CODE FROM CUSTOMER WHERE (CUST_ID = 100)
1398883197030|0|1|statement|SELECT ORDER_ID, OREDER_DESC, ORDER_DATE, TOTAL_PRICE, LAST_UPDATED_TIME, CUST_ID FROM ORDERS WHERE (CUST_ID = ?)|SELECT ORDER_ID, OREDER_DESC, ORDER_DATE, TOTAL_PRICE, LAST_UPDATED_TIME, CUST_ID FROM ORDERS WHERE (CUST_ID = 100)
1398883197037|1|1|statement|SELECT INVOICE_ID, AMOUNT_DUE, DATE_CANCELLED, DATE_RAISED, DATE_SETTLED, LAST_UPDATED_TIME, ORDER_ID FROM ORDER_INVOICE WHERE (ORDER_ID IN (?,?))|SELECT INVOICE_ID, AMOUNT_DUE, DATE_CANCELLED, DATE_RAISED, DATE_SETTLED, LAST_UPDATED_TIME, ORDER_ID FROM ORDER_INVOICE WHERE (ORDER_ID IN (111,222))
1398883197042|1|1|statement|SELECT ORDER_ID, OREDER_DESC, ORDER_DATE, TOTAL_PRICE, LAST_UPDATED_TIME, CUST_ID FROM ORDERS WHERE (ORDER_ID = ?)|SELECT ORDER_ID, OREDER_DESC, ORDER_DATE, TOTAL_PRICE, LAST_UPDATED_TIME, CUST_ID FROM ORDERS WHERE (ORDER_ID = 222)
1398883197045|0|1|statement|SELECT INVOICE_ID, AMOUNT_DUE, DATE_CANCELLED, DATE_RAISED, DATE_SETTLED, LAST_UPDATED_TIME, ORDER_ID FROM ORDER_INVOICE WHERE (ORDER_ID = ?)|SELECT INVOICE_ID, AMOUNT_DUE, DATE_CANCELLED, DATE_RAISED, DATE_SETTLED, LAST_UPDATED_TIME, ORDER_ID FROM ORDER_INVOICE WHERE (ORDER_ID = 222)
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我不明白为什么生成最后两个查询.任何帮助解释正在发生的事情都会有所帮助.
谢谢!
Chr*_*ris 12
看起来像EclipseLink中的一个错误/问题,因为在对象模型中遍历了急切的关系,允许在引用它的Order加载之前在"in"中加载第二个Invoice.这会强制Invoice在数据库中查询Order,而不是在缓存中查找.
您可以通过在Invoice to Order关系上使用延迟提取来解决此问题.此延迟将允许EclipseLink完全构建对象模型,以便在访问时它将位于缓存中.问题中的代码显示此关系标记为Lazy,但这只是JPA提供程序的一个提示,如果不使用代理或字节代码编织而无法在EclipseLink中工作,如下所述:https : //wiki.eclipse.org/EclipseLink/UserGuide/JPA/Advanced_JPA_Development/Performance/Weaving https://wiki.eclipse.org/EclipseLink/UserGuide/JPA/Advanced_JPA_Development/Performance/Weaving/Dynamic_Weaving
延迟集合不需要编织,仅适用于1:1和其他优化.
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