PHP - json_encode(字符串,JSON_UNESCAPED_UNICODE)没有逃避捷克字符

Question

我正在从数据库中选择一些数据并将它们编码为json,但我遇到了类似捷克标志的问题

A,I,R,C,Z ...

我的文件是utf-8编码,我的数据库也是utf-8编码,我也设置了头文件到utf-8编码.我还应该做什么？

我的代码:

header('Content-Type: text/html; charset=utf-8');
while($tmprow = mysqli_fetch_array($result)) {
        $row['user'] = mb_convert_encoding($tmprow['user'], "UTF-8", "auto");
        $row['package'] = mb_convert_encoding($tmprow['package'], "UTF-8", "auto");
        $row['url'] = mb_convert_encoding($tmprow['url'], "UTF-8", "auto");
        $row['rating'] = mb_convert_encoding($tmprow['rating'], "UTF-8", "auto");

        array_push($response, $row);
    }

    $json = json_encode($response, JSON_UNESCAPED_UNICODE);

    if(!$json) {
        echo "error";
    }

和部分印刷的json: "package":"zv???tkanalouce"

编辑:没有mb_convert_encoding()函数,打印的字符串为空,并打印"错误".

Answer 1

使用您在示例中获得的代码,输出为:

json_encode($response, JSON_UNESCAPED_UNICODE);
"package":"zv???tkanalouce"

你在那里看到了问号,因为它们已被引入mb_convert_encoding.当您使用编码检测(" auto"作为第三个参数)并且编码检测无法处理输入中的字符,将其替换为问号时,会发生这种情况.示例性代码行:

$row['url'] = mb_convert_encoding($tmprow['url'], "UTF-8", "auto");

这也意味着来自数据库的数据不是 UTF-8编码的,因为mb_convert_encoding($buffer, 'UTF-8', 'auto');如果$buffer是UTF-8编码则不会引入问号.

因此,您需要找出数据库连接中使用的字符集,因为数据库驱动程序会将字符串转换为连接的编码.

最简单的是你只需告诉每个数据库链接你要求UTF-8字符串然后只使用它们:

$mysqli = new mysqli("localhost", "my_user", "my_password", "test");

/* check connection */
if (mysqli_connect_errno()) {
    printf("Connect failed: %s\n", mysqli_connect_error());
    exit();
}

/* change character set to utf8 */
if (!$mysqli->set_charset("utf8")) {
    printf("Error loading character set utf8: %s\n", $mysqli->error);
} else {
    printf("Current character set: %s\n", $mysqli->character_set_name());
}

前面的代码示例演示了如何使用mysqli将默认客户端字符集设置为UTF-8.它已经从手册中获取,请参阅我们现场的材料,例如utf 8 - PHP和MySQLi UTF8.

然后,您可以大大改善您的代码:

$response = $result->fetch_all(MYSQLI_ASSOC);

$json = json_encode($response, JSON_UNESCAPED_UNICODE);

if (FALSE === $json) {
    throw new LogicException(
        sprintf('Not json: %d - %s', json_last_error(), json_last_error_msg())
    );
}

header('Content-Type: application/json'); 
echo $json;