Python访问嵌套的JSON数据

Question

我正在尝试使用zippopotam.us获取特定城市的邮政编码.我有以下代码可用,除非我尝试访问post code返回的键TypeError: expected string or buffer

r = requests.get('http://api.zippopotam.us/us/ma/belmont')
j = r.json()

data = json.loads(j)

print j['state']
print data['places']['latitude']

完整的JSON输出:

{
"country abbreviation": "US",
"places": [
    {
        "place name": "Belmont",
        "longitude": "-71.4594",
        "post code": "02178",
        "latitude": "42.4464"
    },
    {
        "place name": "Belmont",
        "longitude": "-71.2044",
        "post code": "02478",
        "latitude": "42.4128"
    }
],
"country": "United States",
"place name": "Belmont",
"state": "Massachusetts",
"state abbreviation": "MA"
}

谢谢你的帮助.

Answer 1

地方是一个列表而不是字典.因此,以下这一行不适用:

print data['places']['latitude']

您需要选择其中一个项目,然后您可以列出该地点的属性.所以要获得你要做的第一个帖子代码:

print data['places'][0]['post code']

Answer 2

我没有意识到第一个嵌套元素实际上是一个数组.访问邮政编码密钥的正确方法如下:

r = requests.get('http://api.zippopotam.us/us/ma/belmont')
j = r.json()

print j['state']
print j['places'][1]['post code']

Answer 3

在你的代码中,j是已经是json数据而j ['places']是list而不是dict.

 r = requests.get('http://api.zippopotam.us/us/ma/belmont')
 j = r.json()

 print j['state']
 for each in j['places']:
    print each['latitude']

Answer 4

我正在使用此lib来访问嵌套的dict键

https://github.com/mewwts/addict

 import requests
 from addict import Dict
 r = requests.get('http://api.zippopotam.us/us/ma/belmont')
 ad = Dict(r.json())

 print j.state
 print j.places[1]['post code']  # only work with keys without '-', space, or starting with number