CMS*_*CMS 37

IF EXISTS ( SELECT * FROM INFORMATION_SCHEMA.COLUMNS
WHERE  TABLE_NAME='tablename' AND COLUMN_NAME='columname' )
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Dee*_*dav 8

If col_length('table_name','column_name') is null
    select 0 as Present
ELSE
    select 1 as Present
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Present将为0,table_name中是否存在column_name,否则为1

@CMS:我不认为'INFORMATION_SCHEMA.COLUMNS'有关于DB中每个表的信息.因为这对我没用.但我的回答确实有效.


use*_*358 5

在查询分析器中,选择包含该表的数据库,您需要在其中检查该字段是否存在,然后运行以下查询。

SELECT count(*) AS [Column Exists] 
FROM SYSOBJECTS  
INNER JOIN SYSCOLUMNS ON SYSOBJECTS.ID = SYSCOLUMNS.ID 
WHERE 
 SYSOBJECTS.NAME = 'myTable' 
 AND SYSCOLUMNS.NAME = 'Myfield'
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