use*_*599 7 python json http python-requests
import requests
r = requests.get('http://httpbin.org/get');
r.text
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收益:
u'{\n "url": "http://httpbin.org/get",\n "headers": {\n "Host": "httpbin.org",\n "Accept-Encoding": "gzip, deflate, compress",\n "Connection": "close",\n "Accept": "*/*",\n "User-Agent": "python-requests/2.2.1 CPython/2.7.5 Windows/7",\n "X-Request-Id": "db302999-d07f-4dd6-8c1e-14db45d39fb0"\n },\n "origin": "61.228.172.190",\n "args": {}\n}'
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如何获得origin
和headers/Host
价值观?
谢谢
Eri*_*lun 17
返回的是一个JSON字符串; 你需要解析它才能方便地使用它.如果您致电r.json()
而不是,请求可以为您执行此操作r.text
.
那么这只是做的事情:
resp = r.json()
print resp['origin']
print resp['headers']['Host']
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