(Unity 2D)当它离开屏幕时销毁实例化的预制件？

Question

林做一个2D游戏在Unity 2D(4.3),我需要销毁时,这些组合屋去关闭屏幕实例化的组合屋.我已经编写了一些代码来生成Objects,但是当我们离开屏幕时我想要删除那些预制件.这是我到目前为止编写的代码.

要生成预制件(C#):

void Update () {
    float y = Random.Range(-4.53f, 2.207f);
    if(x < 2000) {
        Instantiate(obstacle, new Vector3(y, x * 6.0f, 0),Quaternion.identity);
        x++;
    }
    //Debug.Log(x);

}

要销毁预制件(C#):

    /*************************************************************************************************
     * GET INSTANTIATED OBSTACLE
     * AND DESTROY IT ON EXIT
     * TO SAVE MEMORY
    **************************************************************************************************/
    GameObject clone = (GameObject)Instantiate (obstacle);

    /*if(clone.transform.position.y == -11)
    {
        Destroy(clone);
        Debug.Log("Destroy");
    }*/

    Vector2 screenPosition = Camera.main.WorldToScreenPoint(transform.position);
    if (screenPosition.y > Screen.height || screenPosition.y < 0)
    {
        Destroy(gameObject);
        Debug.Log("Destroy");
    }

但是,销毁对象的代码不起作用,但也没有出现错误.在预制件离开屏幕后输出"Destroy",所以我知道破坏它们的代码有问题.

谢谢

Answer 1

当位置不在相机位置时,您可以制作一个会破坏自身的组件,然后将此组件附加到障碍物上.

void Update() {
    float y = Random.Range(-4.53f, 2.207f);
    if(x < 2000) {
        GameObject clone = (GameObject)Instantiate(obstacle, new Vector3(y, x * 6.0f, 0),Quaternion.identity);
        clone.AddComponent(typeof(DestroyMySelf));
        x++;
    }
}

并且这个组件附着在障碍物上会破坏自我.

public class DestroyMySelf : MonoBehaviour {
    void Update() {
        Vector2 screenPosition = Camera.main.WorldToScreenPoint(transform.position);
        if (screenPosition.y > Screen.height || screenPosition.y < 0)
        Destroy(this.gameObject);
    }
}