如何将selenium浏览器带到前面？

Question

如果浏览器窗口在bg中,则该行不起作用.

from selenium import webdriver

from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
# available since 2.4.0
from selenium.webdriver.support.ui import WebDriverWait
# available since 2.26.0
from selenium.webdriver.support import expected_conditions as EC

browser = webdriver.Firefox()
browser.get(someWebPage)

element = WebDriverWait(browser, 10).until(
    EC.element_to_be_clickable((By.XPATH, '//button[contains(., "Watch")]')))

elements = browser.find_elements_by_xpath('//button[contains(., "Watch")]')
if elements:
    print 'find watch button',elements
    elements[0].click()

它出错了

  File "myScript.py", line 1469, in getSignedUrl
    EC.element_to_be_clickable((By.XPATH, '//button[contains(., "Watch")]')))
  File "C:\Python27\lib\site-packages\selenium\webdriver\support\wait.py", line 71, in until
    raise TimeoutException(message)
TimeoutException: Message: ''

但如果我将浏览器窗口留在前面,它就不会出错.是因为我不应该使用 EC.element_to_be_clickable？我试图忽略错误并继续单击我想要的按钮,但它说如果浏览器窗口在后台它找不到按钮.所以我认为我应该做的是在它之前,我把浏览器窗口带到前台？

我看到有人在讨论 switchTo()？但是我的浏览器对象没有那种方法.我该怎么做才能将窗口独立地带到前端系统？谢谢

测试系统

python 2.7 windows 7 x64

python 2.6.6 CentOS 6.4

编辑:我试过了

browser.execute_script("window.focus();")

和

# commented out EC.element_to_be_clickable as suggested by alecxe
# element = WebDriverWait(browser, 20).until(
#     EC.element_to_be_clickable((By.XPATH, '//button[contains(., "Watch")]')))
print 'sleeping 5'
time.sleep(5)
elements = browser.find_elements_by_xpath('//button[contains(., "Watch")]')

print 'before clicking'

from selenium.webdriver.common.action_chains import ActionChains
hover = ActionChains(browser).move_to_element(elements[0])
hover.perform()

print elements
elements[0].click()

不工作

edit2:我检查了文档

class selenium.webdriver.support.expected_conditions.element_to_be_clickable(locator)[source]

    An Expectation for checking an element is visible and enabled such that you can click it.

似乎因为当窗口处于bg或最小化时,元素不是"可见的",所以这个条件永远不会被满足？无论如何我尝试了另一种情况

class selenium.webdriver.support.expected_conditions.presence_of_element_located(locator)[source]

    An expectation for checking that an element is present on the DOM of a page. This does not necessarily mean that the element is visible. locator - used to find the element returns the WebElement once it is located

看起来这个工作正常.以前我尝试完全删除条件,它不起作用可能只是因为我没有"等待"很长时间(睡眠5秒)足够.

edit3:奇怪的是,相同的代码在使用selenium 2.39 python 2.6.6 firefox 28 centos 6.4的计算机上工作正常,即使浏览器窗口最小化也是如此.但同样的代码尝试了另外两台机器失败,浏览器窗口必须最大化,按钮必须"可见"A. win7 x64 firefox 28 selenium 2.41 python2.7 B. Fedora 20 firefox 28 selenium 2.41 python2.7

Answer 1

这对我有用，可以将浏览器窗口置于前台。我在 Python 3 上的 Selenium 3.6.0 上使用 chromedriver 进行了测试。

from selenium import webdriver

driver = webdriver.Chrome()

driver.switch_to.window(driver.current_window_handle)

Java 中的相关答案 - https://sqa.stackexchange.com/questions/16428/how-can-i-bring-chrome-browser-to-focus-when-running-a-selenium-test-using-chrom

Answer 2

要回答原始问题,您需要使用最大化窗口方法让浏览器重新获得焦点并置于前台.在Python中它应该是这样的:

browser.maximize_window()