Per*_*ses 9 python xml unicode lxml invalid-characters
众所周知,XML文档中不允许使用某些字符范围.我知道过滤掉这些字符的解决方案(如[1],[2]).
按照不要重复自己的原则,我宁愿在一个中心点实现其中一个解决方案 - 现在,我必须在输入之前清理任何可能不安全的文本lxml
.有没有办法实现这一点,例如通过继承lxml
过滤器类,捕获一些异常或设置配置开关?
编辑:希望有点澄清这个问题,这里是一个示例代码:
from lxml import etree
root = etree.Element("root")
root.text = u'\uffff'
root.text += u'\ud800'
print(etree.tostring(root))
root.text += '\x02'.decode("utf-8")
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执行此操作会得到结果
<root>�</root>
Traceback (most recent call last):
File "[…]", line 9, in <module>
root.text += u'\u0002'
File "lxml.etree.pyx", line 953, in lxml.etree._Element.text.__set__ (src/lxml/lxml.etree.c:44956)
File "apihelpers.pxi", line 677, in lxml.etree._setNodeText (src/lxml/lxml.etree.c:20273)
File "apihelpers.pxi", line 1395, in lxml.etree._utf8 (src/lxml/lxml.etree.c:26485)
ValueError: All strings must be XML compatible: Unicode or ASCII, no NULL bytes or control characters
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如您所见,2字节抛出异常,但lxml很高兴地逃避了另外两个超出范围的字符.真正的麻烦在于
s = "<root>�</root>"
root = etree.fromstring(s)
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也抛出一个例外.在我看来,这种行为有点令人不安,特别是因为它产生了无效的XML文档.
事实证明,这可能是一个2比3的问题.使用python3.4,上面的代码抛出异常
Traceback (most recent call last):
File "[…]", line 5, in <module>
root.text += u'\ud800'
File "lxml.etree.pyx", line 953, in lxml.etree._Element.text.__set__ (src/lxml/lxml.etree.c:44971)
File "apihelpers.pxi", line 677, in lxml.etree._setNodeText (src/lxml/lxml.etree.c:20273)
File "apihelpers.pxi", line 1387, in lxml.etree._utf8 (src/lxml/lxml.etree.c:26380)
UnicodeEncodeError: 'utf-8' codec can't encode character '\ud800' in position 1: surrogates not allowed
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唯一剩下的问题是\uffff
角色,它lxml
仍然乐于接受.
只需在用 LXML 解析字符串之前过滤该字符串即可:从 XML 中清除无效字符(要点为 lawlesst)。
我用你的代码试过了;它似乎有效,但您需要更改要点以导入re和sys!
from lxml import etree
from cleaner import invalid_xml_remove
root = etree.Element("root")
root.text = u'\uffff'
root.text += u'\ud800'
print(etree.tostring(root))
root.text += invalid_xml_remove('\x02'.decode("utf-8"))
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