python object()不带参数错误

eat*_*hil 48 python

我不敢相信这实际上是一个问题,但我一直在尝试调试这个错误而且我无处可去.我确定我错过了一些非常简单的东西,因为这看起来很傻.

import Experiences, Places, Countries
class Experience(object):

    def make_place(self, place):
        addr = place["address"]
        addr = Places.ttypes.Address(addr["street"], addr["city"], addr["state"], Countries.ttypes._NAMES_TO_VALUES[addr["country"]], addr["zipcode"])
        ll = Geocoder.geocode(addr["street"]+", "+addr["city"]+", "+addr["state"]+" "+addr["zipcode"])
        place["location"] = Places.ttypes.Location(ll[0].coordinates[0], ll[0].coordinates[1])

    def __init__(self, exp_dict):
        exp_dict["datetimeInterval"] = Experiences.ttypes.DateTimeInterval(remove(exp_dict, "startTime"), remove(exp_dict, "endTime"))
        exp_dict["type"] = Experiences.ttypes.ExperienceType.OPEN
        exp_dict["place"] = self.make_place(exp_dict["place"])
        self.obj = Experiences.ttypes.Experience(**exp_dict)

@client.request
@client.catchClientException
def addExperience(thrift, access_token, exp_dict):
    experience = Experience(exp_dict)
    return thrift.client.addExperience(thrift.CLIENT_KEY, access_token, experience.obj)
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(对应于addExperience的两个装饰器是因为它是在声明其类的文件之外定义的.)

我得到的错误是:

experience = Experience(exp_dict)
TypeError: object() takes no parameters
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所以这对我没有任何意义,因为我明确地声明了init函数的第二个参数.任何帮助都是极好的!

Traceback (most recent call last):
  File "/Users/phil/Hangify/hy-frontend-server/env/lib/python2.7/site-packages/flask/app.py", line 1836, in __call__
    return self.wsgi_app(environ, start_response)
  File "/Users/phil/Hangify/hy-frontend-server/env/lib/python2.7/site-packages/flask/app.py", line 1820, in wsgi_app
    response = self.make_response(self.handle_exception(e))
  File "/Users/phil/Hangify/hy-frontend-server/env/lib/python2.7/site-packages/flask/app.py", line 1403, in handle_exception
    reraise(exc_type, exc_value, tb)
  File "/Users/phil/Hangify/hy-frontend-server/env/lib/python2.7/site-packages/flask/app.py", line 1817, in wsgi_app
    response = self.full_dispatch_request()
  File "/Users/phil/Hangify/hy-frontend-server/env/lib/python2.7/site-packages/flask/app.py", line 1477, in full_dispatch_request
    rv = self.handle_user_exception(e)
  File "/Users/phil/Hangify/hy-frontend-server/env/lib/python2.7/site-packages/flask/app.py", line 1381, in handle_user_exception
    reraise(exc_type, exc_value, tb)
  File "/Users/phil/Hangify/hy-frontend-server/env/lib/python2.7/site-packages/flask/app.py", line 1475, in full_dispatch_request
    rv = self.dispatch_request()
  File "/Users/phil/Hangify/hy-frontend-server/env/lib/python2.7/site-    packages/flask/app.py", line 1461, in dispatch_request
    return self.view_functions[rule.endpoint](**req.view_args)
  File "/Users/phil/Hangify/hy-frontend-server/hangify/session.py", line 22, in check_login
    return f()
  File "/Users/phil/Hangify/hy-frontend-server/hangify/handlers/create.py", line 31, in Handle
    res = exp.addExperience(hangify.thrift_interface, access_token, experience)
  File "/Users/phil/Hangify/hy-frontend-server/hangify/client/__init__.py", line 22, in decorator
    obj = func(client, *args, **kwargs)
  File "/Users/phil/Hangify/hy-frontend-server/hangify/client/__init__.py", line 30, in decorator
    return func(*args, **kwargs)
  File "/Users/phil/Hangify/hy-frontend-server/hangify/client/exp.py", line 39, in addExperience
    experience = Experience(exp_dict)
TypeError: object() takes no parameters
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这是Experience.mro() - 它表示类体验的正确模块位置:

[<class 'hangify.client.exp.Experience'>, <type 'object'>]
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这是dir(经验):

 ['__class__', '__delattr__', '__dict__', '__doc__', '__format__',
 '__getattribute__', '__hash__', '__init__', '__module__', '__new__',
 '__reduce__', '__reduce_ex__', '__repr__', '__setattr__',
 '__sizeof__', '__str__', '__subclasshook__', '__weakref__', 'make_place']
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use*_*ica 68

你混合了标签和空格.__init__实际上是嵌套在另一个方法中,所以你的类没有自己的__init__方法,而是继承它object.__init__.在记事本中打开您的代码而不是您正在使用的任何编辑器,您将看到您的代码,因为Python的选项卡处理规则可以看到它.

这就是为什么你不应该混合标签和空格.坚持一个或另一个.建议使用空格.


小智 43

关于这一点,我挣扎了一段时间.愚蠢的规则__init__.它是两个"_"一起成为"__"

  • 得到这个错误,因为我很草率,只写了`__init()` (5认同)

Naf*_*shi 23

我也得到了这个错误.顺便说一句,我键入__int__而不是__init__.

我认为,在许多错误的情况下,我使用的IDE(IntelliJ)会将颜色更改为功能定义的默认设置.但是,在我的情况下__int__是另一个dunder/magic方法,颜色与IDE为__init__(默认的预定义项目定义颜色)显示的颜色保持相同,这花了我一些时间来发现丢失的i.

  • 哈哈,我犯了同样的错误,但找不到它。您的评论帮助我交叉检查了我使用的默认方法。谢谢 :) (2认同)

小智 9

您必须_每次按两次并按()键,它必须如下所示:

__init__
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  • 问题包含正确的`__init__`. (3认同)