在我下面的代码中,我想循环直到用户提供正确的输入。但是当我尝试时,它变成了一个不间断的循环。
Please Enter Valid Input.
如果没有 while 循环,它也是一样的。
这里有while循环:
#include <iostream>
#include <fstream>
#include <string>
#include <ctime>
#include <sstream>
using namespace std;
class library {
public:
library() {
int mainOption;
cout<<"Please choose the option you want to perform."<<endl;
cout<<"1. Member Section"<<"\n"<<"2. Books, Lending & Donate Section"<<"\n"<<"3. Returning Section"<<endl;
bool option=true;
while (option==true) {
cin>>mainOption;
if (mainOption==1) {
cout<<"section 1"<<endl;
option=false;
} else if (mainOption==2) {
cout<<"section 1"<<endl;
option=false;
} else if (mainOption==3) {
cout<<"section 1"<<endl;
option=false;
} else {
cout<<"Please Enter Valid Input. "<<endl;
//option still true. so it should ask user input again right?
}
}
}
};
int main(int argc, const char * argv[])
{
library l1;
return 0;
}
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这里没有while循环。但同样的事情正在发生。
#include <iostream>
#include <fstream>
#include <string>
#include <ctime>
#include <sstream>
using namespace std;
class library {
public:
library() {
int mainOption;
cout<<"Please choose the option you want to perform."<<endl;
cout<<"1. Member Section"<<"\n"<<"2. Books, Lending & Donate Section"<<"\n"<<"3. Returning Section"<<endl;
cin>>mainOption;
if (mainOption==1) {
cout<<"section 1"<<endl;
} else if (mainOption==2) {
cout<<"section 1"<<endl;
} else if (mainOption==3) {
cout<<"section 1"<<endl;
} else {
cout<<"Please Enter Valid Input. "<<endl;
library();//Calling library function again to input again.
}
}
};
int main(int argc, const char * argv[])
{
library l1;
return 0;
}
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问题是当你打电话
cin>>mainOption; // mainOption is an int
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但用户没有输入int,cin将输入缓冲区留在旧状态。除非您的代码消耗了输入的无效部分,否则最终用户输入的错误值将保留在缓冲区中,从而导致无限重复。
这是您解决此问题的方法:
} else {
cout<<"Please Enter Valid Input. "<<endl;
cin.clear(); // Clear the error state
string discard;
getline(cin, discard); // Read and discard the next line
// option remains true, so the loop continues
}
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请注意,我还删除了递归,因为您的while循环足以处理手头的任务。