ng-grid:如何显示true/false值的复选框

Question

在angularjs脚本中,我有"ng-grid"模块,在一列中,我想显示复选框控件而不是从json数据返回的true/false字符串.如果json变量为true,则必须选中该复选框,如果为false,则必须选中该复选框.

我想我必须使用模板,但我不知道如何.

如何显示复选框？有一些例子吗？

谢谢

Answer 1

像这样:用更改处理程序更新

    var app = angular.module('myApp', ['ngGrid']);
    app.controller('MyCtrl', function($scope) {
      $scope.myData = [{
        name: "Moroni",
        age: 50,
        dude: true
      }, {
        name: "Tiancum",
        age: 43,
        dude: true
      }, {
        name: "Jacob",
        age: 27,
        dude: false
      }, {
        name: "Nephi",
        age: 29,
        dude: true
      }, {
        name: "Enos",
        age: 34,
        dude: false
      }];
      $scope.gridOptions = {
        data: 'myData',
        columnDefs: [{
          field: 'name',
          displayName: 'Name'
        }, {
          field: 'age',
          displayName: 'Age'
        }, {
          field: 'dude',
          displayName: 'Dude',
          cellTemplate: '<input type="checkbox" ng-model="row.entity.dude" ng-click="toggle(row.entity.name,row.entity.dude)">'
        }]
      };

      $scope.toggle = function(name, value) {
        //do something usefull here, you have the name and the new value of dude. Write it to a db or else. 
        alert(name + ':' + value);
      }
    });

您现在可以添加更改处理程序,或者只是将输入设置为禁用/只读,如果您只想显示该值.

Plunker

带有更换处理程序的Plunker

(我很抱歉雅各布和伊诺斯!)