Spo*_*ort 2 javascript jquery backbone.js backbone-views
我遇到了一个问题.我CommentinfoModel是从服务器获取数据,我能够在视图中显示所有数据.我用另一个PostwallModel在同一视图中发布数据.
当我发布数据时,我从服务器获得响应,但该数据不会出现在模板中.当我转到另一页并回来时,会显示新发布的数据.完成后的帖子操作后如何刷新.这是我的代码:
var myPostwallView = Backbone.View.extend({
el: $("#content"),
events: {
'click #postinwall': 'postmessage',
},
initialize: function () {
var that = this;
var options = {
query: uni_id + "/chaid/" + currentChallenge['id']
}
var onDataHandler = function (collection) {
that.render();
}
var onErrorHandler = function (collection) {
var errorstring = JSON.stringify(collection);
console.log(errorstring);
}
this.model = new CommentinfoModel(options);
this.model.fetch({
success: onDataHandler,
error: onErrorHandler,
dataType: "json"
});
},
render: function () {
$('.nav li').removeClass('active');
$('.nav li a[href="' + window.location.hash + '"]').parent().addClass('active');
var data = {
cinfo: this.model.toJSON(),
_: _
};
var compiledTemplate = _.template(PostwallTemplate, {
data: data
});
this.$el.html(compiledTemplate);
},
// Posting message action
postmessage: function (e) {
var optionsp = {
query: uni_id + "/chaid/" + currentChallenge['id']
}
var postmsg = $('#txt').val();
var obj = new PostwallModel(optionsp);
obj.save({
uid: uni_id,
chaid: currentChallenge['id'],
post: postmsg
}, {
success: function (obj, response) {
console.log(response.responseText, console.log(response);
alert(response.message));
}
});
e.preventDefault();
$('#txt').val("");
}
});
return myPostwallView;
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小智 6
当完成诸如GET或POST之类的主干操作时,模型将触发您可以在视图上侦听的同步事件并调用您的渲染功能.该代码看起来像这样,可以放在您的视图初始化方法中:
this.listenTo(this.model, 'sync', this.render);
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