Jry*_*972 2 python matplotlib pie-chart
在以下代码中,只要鼠标单击饼图,我就在控制台上打印标签。问题是由于楔块的原因,我无法将autopct添加到ax.pie()中,我不知道如何在不使用autopct的情况下在饼图上添加百分比标签。
import matplotlib.pyplot as plt
labels = ['Beans', 'Squash', 'Corn']
i=0
def main():
# Make an example pie plot
fig = plt.figure()
ax = fig.add_subplot(111)
#labels = ['Beans', 'Squash', 'Corn']
wedges, plt_labels = ax.pie([20, 40, 60], labels=labels)
ax.axis('equal')
make_picker(fig, wedges)
plt.show()
def make_picker(fig, wedges):
global i
def onclick(event):
global i
i=i+1
print event.__class__
wedge = event.artist
label = wedge.get_label()
print label
fig.canvas.figure.clf()
ax=fig.add_subplot(111)
wedges, plt_labels = ax.pie([50, 100, 60],labels=labels)# how to add autopct='%1.1f%%'
fig.canvas.draw()
for wedge in wedges:
wedge.set_picker(True)
# Make wedges selectable
if i==0:
for wedge in wedges:
wedge.set_picker(True)
fig.canvas.mpl_connect('pick_event', onclick)
if __name__ == '__main__':
main()
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如果要使用autopct,请记住现在要解压缩的是3个值,而不是2个,因此更改代码以wedges, plt_labels, junk = ax.pie([20, 40, 60], labels=labels, autopct='%1.1f%%')解决问题
juck将成为text.Text您的百分比值的对象。
