如何在SQL Server中将XML数据转换为行列数据

pal*_*ukh 3 xml sql-server types row calculated-columns

我有一个在数据库中有XML数据的需求,我需要从数据库中提取行和列的形式。我的XML就像

<Equipment>
<EquipmentRecord>
<EquipmentType>E</EquipmentType><MfgName>APPLE iPH564WHT</MfgName><Model>885909600205</Model><ActDate>10/26/2012</ActDate><CancelDate />
</EquipmentRecord>
<EquipmentRecord>
<EquipmentType>E</EquipmentType><MfgName>SAMSUNG D710 HANDSET KIT</MfgName><Model>SPHD710KIT</Model><ActDate>09/04/2012</ActDate><CancelDate>10/01/2012</CancelDate>
</EquipmentRecord>
<EquipmentRecord>
<EquipmentType>E</EquipmentType><MfgName>BLACKBERRY 9670 PURPLE</MfgName><Model>SPRIM9670P</Model><ActDate>08/22/2012</ActDate><CancelDate>08/25/2012</CancelDate>
</EquipmentRecord>
</Equipment>
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我希望数据像

EquipmentType   MfgName                 Model           ActDate     CancelDate
E             APPLE iPH564WHT           885909600205    10/26/2012  
E             SAMSUNG D710 HANDSET KIT  SPHD710KIT      09/04/2012  10/01/2012
E             BLACKBERRY 9670 PURPLE    SPRIM9670P      08/22/2012  08/25/2012
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在SQL Server中有什么简单的方法吗?

我尝试了并且成功了

DECLARE @doc XML
SET @doc = 'above XML'  

CREATE TABLE #EquipmentType (ID INT IDENTITY(1,1), EquipmentType varchar(100))
INSERT INTO #EquipmentType(EquipmentType)
SELECT EquipmentDetails.value('.','varchar(100)') as EquipmentType
FROM @doc.nodes('/Equipment/EquipmentRecord/EquipmentType/.') Equipment(EquipmentDetails)

CREATE TABLE #MfgName (ID INT IDENTITY(1,1), MfgName varchar(500))
INSERT INTO #MfgName(MfgName)
SELECT EquipmentDetails.value('.','varchar(500)') as MfgName
FROM @doc.nodes('/Equipment/EquipmentRecord/MfgName/.') Equipment(EquipmentDetails)

CREATE TABLE #Model (ID INT IDENTITY(1,1), Model varchar(500))
INSERT INTO #Model(Model)
SELECT EquipmentDetails.value('.','varchar(500)') as Model
FROM @doc.nodes('/Equipment/EquipmentRecord/Model/.') Equipment(EquipmentDetails)

CREATE TABLE #ActDate (ID INT IDENTITY(1,1), ActDate varchar(500))
INSERT INTO #ActDate(ActDate)
SELECT EquipmentDetails.value('.','varchar(500)') as ActDate
FROM @doc.nodes('/Equipment/EquipmentRecord/ActDate/.') Equipment(EquipmentDetails)

CREATE TABLE #CancelDate (ID INT IDENTITY(1,1), CancelDate varchar(500))
INSERT INTO #CancelDate(CancelDate)
SELECT EquipmentDetails.value('.','varchar(500)') as CancelDate
FROM @doc.nodes('/Equipment/EquipmentRecord/CancelDate/.') Equipment(EquipmentDetails)

SELECT EquipmentType,MfgName,Model,ActDate,CancelDate 
FROM #EquipmentType ET
Inner Join #MfgName MN ON (ET.ID = MN.ID)
Inner Join #Model MO ON (MN.ID = MO.ID)
Inner Join #ActDate AD ON (MO.ID = AD.ID)
Inner Join #CancelDate CD ON (AD.ID = CD.ID)

DROP TABLE #EquipmentType
DROP TABLE #MfgName
DROP TABLE #Model
DROP TABLE #ActDate
DROP TABLE #CancelDate
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但我想要一个简单的方法来做到这一点?

小智 6

以下查询应该工作:

declare @X xml = 'your xml';

select  x.r.value('(EquipmentType)[1]', 'varchar(100)') as [EquipmentType],
    x.r.value('(MfgName)[1]', 'varchar(500)') as [MfgName],
    x.r.value('(Model)[1]', 'varchar(500)') as [Model],
    x.r.value('(ActDate)[1]', 'varchar(500)') as [ActDate],
    x.r.value('(CancelDate)[1]', 'varchar(500)') as [CancelDate]
from    @X.nodes('/Equipment/EquipmentRecord') as x(r);
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