如何在iOS中获得UIView的超级视图的UIViewController？

Question

我有一个UIViewController,我在其中添加了一个从界面构建器添加的UITextView.现在,当我点击超链接或电话号码时,我想推送视图.我能够使用stackoverflow中找到的方法检测到哪个url被点击了.这是方法

@interface UITextView (Override)
@end

@class WebView, WebFrame;
@protocol WebPolicyDecisionListener;

@implementation UITextView (Override)

- (void)webView:(WebView *)webView decidePolicyForNavigationAction:(NSDictionary *)actionInformation request:(NSURLRequest *)request frame:(WebFrame *)frame decisionListener:(id < WebPolicyDecisionListener >)listener
{
    NSLog(@"request: %@", request);
}
@end

现在我想得到textview的superview的viewController,这样当我点击URL/Phone Number时我就可以推送另一个viewController.

Answer 1

您无法直接访问它,但您可以通过遍历响应程序链找到下一个视图控制器(如果有).

这就是Three20框架的作用:

- (UIViewController*)viewController
{
    for (UIView* next = [self superview]; next; next = next.superview)
    {
        UIResponder* nextResponder = [next nextResponder];

        if ([nextResponder isKindOfClass:[UIViewController class]])
        {
            return (UIViewController*)nextResponder;
        }
    }

    return nil;
}