通过仅指定列大小将数组重新整形为2-D

T-8*_*800 13 python numpy python-2.x

我有一个长度的矢量,让我们说10:

foo = np.arange(2,12)
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为了将它转换为2-D数组,让我们说2列,我使用reshape带有以下参数的命令:

foo.reshape(len(foo)/2, 2)
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我想知道是否有更优雅的方式/语法来做(可能是某样的foo.reshape(,2))

DSM*_*DSM 25

你几乎拥有它!你可以用-1.

>>> foo.reshape(-1, 2)
array([[ 2,  3],
       [ 4,  5],
       [ 6,  7],
       [ 8,  9],
       [10, 11]])
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正如reshape文档所说:

newshape : int or tuple of ints
    The new shape should be compatible with the original shape. If
    an integer, then the result will be a 1-D array of that length.
    One shape dimension can be -1. In this case, the value is inferred
    from the length of the array and remaining dimensions.
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