Android如何创建弹出窗口

use*_*352 6 android window popup button

我需要创建一个带有按钮的弹出窗口和一个关闭弹出窗口的按钮.我找到了一些教程,但我找不到如何进行实施.

我想做什么:单击一个操作按钮,弹出窗口显示,当我单击关闭按钮时,弹出窗口必须关闭.

在tuorial中有一个onCreate方法,我不明白它是如何调用的.

有人可以举一个弹出式实现的例子或一个好教程的链接吗?谢谢!

小智 7

private void showPopup(){
    Button btn_closepopup=(Button)layout.findViewById(R.id.btn_closePoppup);
    pwindo=new PopupWindow(layout,480,500,true);
    pwindo.showAtLocation(layout, Gravity.CENTER, 0, 40);
    chartContainer1.addView(mChart);
    btn_closepopup.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View arg0) {
            // TODO Auto-generated method stub
            pwindo.dismiss();
        }
    });
}
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Dhi*_*a k 6

在此输入图像描述

 private void callPopup() {

 LayoutInflater layoutInflater = (LayoutInflater)getBaseContext()
 .getSystemService(LAYOUT_INFLATER_SERVICE);

View popupView = layoutInflater.inflate(R.layout.popup, null);

 popupWindow=new PopupWindow(popupView,
         LayoutParams.WRAP_CONTENT, LayoutParams.MATCH_PARENT,        
 true);

 popupWindow.setTouchable(true);
 popupWindow.setFocusable(true);

 popupWindow.showAtLocation(popupView, Gravity.CENTER, 0, 0);
 Name = (EditText) popupView.findViewById(R.id.edtimageName);

((Button) popupView.findViewById(R.id.saveBtn))
 .setOnClickListener(new OnClickListener() {

    @TargetApi(Build.VERSION_CODES.GINGERBREAD)
 public void onClick(View arg0) {
 Toast.makeText(getApplicationContext(),
     Name.getText().toString(),Toast.LENGTH_LONG).show();

  popupWindow.dismiss();

 }

});

((Button) popupView.findViewById(R.id.cancelbtutton))
  .setOnClickListener(new OnClickListener() {

  public void onClick(View arg0) {

   popupWindow.dismiss();
  }
});
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