And*_*omi 0 java android android-asynctask
我试图从一个Android活动(一个简单的登录表单)做一个http请求/响应,但在我完成代码后它给了我一个错误,因为我必须把它放在一个线程,我不熟悉异步任务但我我试图实现它但是,现在当我运行程序并点击提交时,logcat给了我类似的东西
FATAL EXCEPTION: AsyncTask #1
Process: com.example.httpgetandroidexample, PID: 1131
java.lang.RuntimeException: An error occured while executing doInBackground()
at android.os.AsyncTask$3.done(AsyncTask.java:300)
at java.util.concurrent.FutureTask.finishCompletion(FutureTask.java:355)
at java.util.concurrent.FutureTask.setException(FutureTask.java:222)
at java.util.concurrent.FutureTask.run(FutureTask.java:242)
at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:231)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1112)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:587)
at java.lang.Thread.run(Thread.java:841)
Caused by: android.view.ViewRootImpl$CalledFromWrongThreadException: Only the original thread that created a view hierarchy can touch its views.
at android.view.ViewRootImpl.checkThread(ViewRootImpl.java:6094)
at android.view.ViewRootImpl.requestLayout(ViewRootImpl.java:824)
at android.view.View.requestLayout(View.java:16431)
at android.view.View.requestLayout(View.java:16431)
at android.view.View.requestLayout(View.java:16431)
at android.view.View.requestLayout(View.java:16431)
at android.widget.RelativeLayout.requestLayout(RelativeLayout.java:352)
at android.view.View.requestLayout(View.java:16431)
at android.widget.TextView.checkForRelayout(TextView.java:6600)
at android.widget.TextView.setText(TextView.java:3813)
at android.widget.TextView.setText(TextView.java:3671)
at android.widget.TextView.setText(TextView.java:3646)
at com.example.httpgetandroidexample.MainActivity$AsyncTaskRunner.doInBackground(MainActivity.java:87)
at com.example.httpgetandroidexample.MainActivity$AsyncTaskRunner.doInBackground(MainActivity.java:1)
at android.os.AsyncTask$2.call(AsyncTask.java:288)
at java.util.concurrent.FutureTask.run(FutureTask.java:237)
... 4 more
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我不明白为什么!这是我的android活动:
package com.example.httpgetandroidexample;
import java.io.UnsupportedEncodingException;
import java.net.URLEncoder;
import org.apache.http.client.HttpClient;
import org.apache.http.client.ResponseHandler;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.BasicResponseHandler;
import org.apache.http.impl.client.DefaultHttpClient;
import android.app.Activity;
import android.os.AsyncTask;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;
import android.widget.Toast;
public class MainActivity extends Activity {
public TextView content;
EditText name,pass;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
name = (EditText)findViewById(R.id.name);
pass = (EditText)findViewById(R.id.pass);
content = (TextView)findViewById(R.id.text);
Button button=(Button)findViewById(R.id.but);
button.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
AsyncTaskRunner runner = new AsyncTaskRunner();
runner.execute();
}
});
}
class AsyncTaskRunner extends AsyncTask<String, String, String> {
private String resp;
@Override
protected String doInBackground(String... params) {
publishProgress("Working..."); // Calls onProgressUpdate()
try{
// URLEncode user defined data
String nameValue = URLEncoder.encode(name.getText().toString(), "UTF-8");
String passValue = URLEncoder.encode(pass.getText().toString(), "UTF-8");
// Create http cliient object to send request to server
HttpClient Client = new DefaultHttpClient();
// Create URL string
String URL = "http://localhost:8080/login/web?user="+nameValue+"&pass="+passValue;
//Log.i("httpget", URL);
try
{
String SetServerString = "";
// Create Request to server and get response
HttpGet httpget = new HttpGet(URL);
ResponseHandler<String> responseHandler = new BasicResponseHandler();
SetServerString = Client.execute(httpget, responseHandler);
// Show response on activity
content.setText(SetServerString);
}
catch(Exception ex)
{
content.setText("fail");
System.out.println(ex);
resp="fail";
}
}
catch(UnsupportedEncodingException ex)
{
content.setText("FailAndroid!");
resp="fail";
}
return resp;
}
@Override
protected void onPostExecute(String result) {
content.setText(result);
}
protected void onPreExecute() {
}
@Override
protected void onProgressUpdate(String... text) {
content.setText(text[0]);
}
}
}
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我的代码显示没有错误,甚至没有警告,但是当我按下提交按钮时,它会在"工作"消息出现后强制关闭,是否有人知道为什么?先感谢您
在你的帮助下(谢谢大家!)我修改了我的活动代码,如下所示:
package com.example.httpgetandroidexample;
import java.io.UnsupportedEncodingException;
import java.net.URLEncoder;
import org.apache.http.client.HttpClient;
import org.apache.http.client.ResponseHandler;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.BasicResponseHandler;
import org.apache.http.impl.client.DefaultHttpClient;
import android.app.Activity;
import android.os.AsyncTask;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;
import android.widget.Toast;
public class MainActivity extends Activity {
public TextView content;
EditText name,pass;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
name = (EditText)findViewById(R.id.name);
pass = (EditText)findViewById(R.id.pass);
content = (TextView)findViewById(R.id.text);
Button button=(Button)findViewById(R.id.but);
button.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
AsyncTaskRunner runner = new AsyncTaskRunner();
runner.execute();
}
});
}
class AsyncTaskRunner extends AsyncTask<String, String, String> {
private String resp;
@Override
protected String doInBackground(String... params) {
publishProgress("Working..."); // Calls onProgressUpdate()
try{
// URLEncode user defined data
String nameValue = URLEncoder.encode(name.getText().toString(), "UTF-8");
String passValue = URLEncoder.encode(pass.getText().toString(), "UTF-8");
// Create http cliient object to send request to server
HttpClient Client = new DefaultHttpClient();
// Create URL string
String URL = "http://localhost:8080/login/web?user="+nameValue+"&pass="+passValue;
//Log.i("httpget", URL);
try
{
String SetServerString = "";
// Create Request to server and get response
HttpGet httpget = new HttpGet(URL);
ResponseHandler<String> responseHandler = new BasicResponseHandler();
SetServerString = Client.execute(httpget, responseHandler);
// Show response on activity
return SetServerString;
}
catch(Exception ex)
{
Log.i("MyActivity","Exception");
}
}
catch(UnsupportedEncodingException ex)
{
Log.i("MyActivity","UnsupportedEncodingException");
}
return resp;
}
@Override
protected void onPostExecute(String result) {
content.setText(result);
}
protected void onPreExecute() {
}
@Override
protected void onProgressUpdate(String... text) {
content.setText(text[0]);
}
}
}
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但现在我得到了我的 Log.i("MyActivity","Exception");信息,我还在做错什么?
UPDATE
而对于我的最后一次尝试,我再次修改了代码,然后在线阅读了一些教程,这就是我所做的
package com.example.httpgetandroidexample;
import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.UnsupportedEncodingException;
import java.net.URLEncoder;
import org.apache.http.HttpResponse;
import org.apache.http.client.HttpClient;
import org.apache.http.client.ResponseHandler;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.BasicResponseHandler;
import org.apache.http.impl.client.DefaultHttpClient;
import android.app.Activity;
import android.os.AsyncTask;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;
import android.widget.Toast;
public class MainActivity extends Activity {
public TextView content;
EditText name,pass;
String URL;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
name = (EditText)findViewById(R.id.name);
pass = (EditText)findViewById(R.id.pass);
content = (TextView)findViewById(R.id.text);
Button button=(Button)findViewById(R.id.but);
try {
String nameValue = URLEncoder.encode(name.getText().toString(), "UTF-8");
String passValue = URLEncoder.encode(pass.getText().toString(), "UTF-8");
URL = "http://localhost:8080/login/web?user="+nameValue+"&pass="+passValue;
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
button.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
AsyncTaskRunner runner = new AsyncTaskRunner();
runner.execute(new String[ ] { URL });
}
});
}
private class AsyncTaskRunner extends AsyncTask<String, Void, String> {
@Override
protected String doInBackground(String... urls) {
String response = "";
for (String url : urls) {
DefaultHttpClient client = new DefaultHttpClient();
HttpGet httpGet = new HttpGet(url);
try {
HttpResponse execute = client.execute(httpGet);
InputStream content = execute.getEntity().getContent();
BufferedReader buffer = new BufferedReader(new InputStreamReader(content));
String s = "";
while ((s = buffer.readLine()) != null) {
response += s;
}
} catch (Exception e) {
e.printStackTrace();
}
}
return response;
}
@Override
protected void onPostExecute(String result) {
content.setText(result);
}
}
}
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这里是详细模式的logcat:
Permission denied (missing INTERNET permission?)
at java.net.InetAddress.lookupHostByName(InetAddress.java:418)
at java.net.InetAddress.getAllByNameImpl(InetAddress.java:236)
at java.net.InetAddress.getAllByName(InetAddress.java:214)
at org.apache.http.impl.conn.DefaultClientConnectionOperator.openConnection(DefaultClientConnectionOperator.java:137)
at org.apache.http.impl.conn.AbstractPoolEntry.open(AbstractPoolEntry.java:164)
at org.apache.http.impl.conn.AbstractPooledConnAdapter.open(AbstractPooledConnAdapter.java:119)
at org.apache.http.impl.client.DefaultRequestDirector.execute(DefaultRequestDirector.java:360)
at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:555)
at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:487)
at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:465)
at com.example.httpgetandroidexample.MainActivity$AsyncTaskRunner.doInBackground(MainActivity.java:69)
at com.example.httpgetandroidexample.MainActivity$AsyncTaskRunner.doInBackground(MainActivity.java:1)
at android.os.AsyncTask$2.call(AsyncTask.java:288)
at java.util.concurrent.FutureTask.run(FutureTask.java:237)
at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:231)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1112)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:587)
at java.lang.Thread.run(Thread.java:841)
Caused by: libcore.io.GaiException: getaddrinfo failed: EAI_NODATA (No address associated with hostname)
at libcore.io.Posix.getaddrinfo(Native Method)
at libcore.io.ForwardingOs.getaddrinfo(ForwardingOs.java:61)
at java.net.InetAddress.lookupHostByName(InetAddress.java:405)
... 17 more
Caused by: libcore.io.ErrnoException: getaddrinfo failed: EACCES (Permission denied)
... 20 more
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从我可以理解它缺少的权限,但问题是我有我的清单文件:
<application
android:allowBackup="true"
android:icon="@drawable/ic_launcher"
android:label="@string/app_name"
android:theme="@style/AppTheme" android:permission="android.permission.INTERNET">
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Logcat错误:
引起:android.view.ViewRootImpl $ CalledFromWrongThreadException:只有创建视图层次结构的原始线程才能触及其视图.
你尝试使用UI线程doInBackground,
content.setText("fail");
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你不能在后台线程中使用onPostExecuteUI 来触摸ui线程中的任何东西
这是你想要的一个样本.
private class DownloadWebPageTask extends AsyncTask<String, Void, String> {
@Override
protected String doInBackground(String... urls) {
String response = "";
for (String url : urls) {
DefaultHttpClient client = new DefaultHttpClient();
HttpGet httpGet = new HttpGet(url);
try {
HttpResponse execute = client.execute(httpGet);
InputStream content = execute.getEntity().getContent();
BufferedReader buffer = new BufferedReader(new InputStreamReader(content));
String s = "";
while ((s = buffer.readLine()) != null) {
response += s;
}
} catch (Exception e) {
e.printStackTrace();
}
}
return response;
}
@Override
protected void onPostExecute(String result) {
textView.setText(result);
}
}
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你需要从中返回你的String doInBackground
在样本中: return response;
返回,你需要改变:
在样本中:
1- AsyncTask<String, Void, String><--- last value是您希望从本网站获得的doInBackground更多信息
2- protected String doInBackground<---将返回类型更改为String
3 - 返回你的价值 return response;
4- protected void onPostExecute(String result) <---这也必须是String
然后使用UI onPostExecute
在Sample onPostExecute(String result) <--- result中是你的String
来自Vogella文章的复制代码 6.5. Example: AsyncTask
UPDATE
您再次使用UI:
String nameValue = URLEncoder.encode(name.getText().toString(), "UTF-8");
String passValue = URLEncoder.encode(pass.getText().toString(), "UTF-8");
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如果你想要这个值,你可以将它们发送到asynctask的构造函数或发送为参数doInBackground,我推荐第二种方式
作为try catch语句中的代码,你的应用程序没有关闭,因为你没有打印任何对catch有用的东西你不能得到你的错误,如果你使用catch它更合适的打印错误太像:
catch(UnsupportedEncodingException ex)
{
ex.printStackTrace();
}
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更新2
您在代码中声明您的Android权限如下:
android:permission="android.permission.INTERNET">
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但你必须添加你的权限,如:
<manifest xlmns:android...>
...
<uses-permission android:name="android.permission.INTERNET"></uses-permission>
</manifest>
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你的清单必须像:
<?xml version="1.0" encoding="utf-8"?>
<manifest
......
......
.....>
<uses-sdk
...... />
<uses-permission android:name="android.permission.INTERNET" />
<application
.......
.......
</application>
</manifest>
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