SQL:选择不在子查询中的表中的所有内容？

Question

此查询似乎运行良好:

-- Every supplier that produces some red or green part
SELECT Suppliers.sid
FROM Suppliers, Catalog, Parts
WHERE Suppliers.sid = Catalog.sid 
    AND Catalog.pid = Parts.pid
    AND (Parts.color = "red" OR Parts.color = "green");

为了检查它,我想查看此查询不会返回的每个SID,以确保它们不会生成绿色或红色部分.我怎样才能做到这一点？

这似乎不起作用:

SELECT Parts.color
FROM Suppliers, Catalog, Parts
WHERE Suppliers.sid NOT IN (    
    SELECT Suppliers.sid, Parts.color
    FROM Suppliers, Catalog, Parts
    WHERE Suppliers.sid = Catalog.sid 
        AND Catalog.pid = Parts.pid
        AND (Parts.color = "red" OR Parts.color = "green")
    );

MySQL错误:

错误1241(21000):操作数应包含1列

什么是正确的方法？

这是用于创建我正在使用的表的SQL:

SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0;
SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0;
SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL';

CREATE SCHEMA IF NOT EXISTS `mydb` DEFAULT CHARACTER SET latin1 COLLATE latin1_swedish_ci ;
USE `mydb`;

-- -----------------------------------------------------
-- Table `mydb`.`Suppliers`
-- -----------------------------------------------------
CREATE  TABLE IF NOT EXISTS `mydb`.`Suppliers` (
  `sid` INT NOT NULL ,
  `sname` VARCHAR(45) NULL ,
  `address` VARCHAR(45) NULL ,
  PRIMARY KEY (`sid`) )
ENGINE = InnoDB;


-- -----------------------------------------------------
-- Table `mydb`.`Parts`
-- -----------------------------------------------------
CREATE  TABLE IF NOT EXISTS `mydb`.`Parts` (
  `pid` INT NOT NULL ,
  `pname` VARCHAR(45) NULL ,
  `color` VARCHAR(45) NULL ,
  PRIMARY KEY (`pid`) )
ENGINE = InnoDB;


-- -----------------------------------------------------
-- Table `mydb`.`Catalog`
-- -----------------------------------------------------
CREATE  TABLE IF NOT EXISTS `mydb`.`Catalog` (
  `cost` INT NULL ,
  `pid` INT NOT NULL ,
  `sid` INT NOT NULL ,
  PRIMARY KEY (`pid`, `sid`) ,
  INDEX `fk_Catalog_Parts1` (`pid` ASC) ,
  INDEX `fk_Catalog_Suppliers1` (`sid` ASC) ,
  CONSTRAINT `fk_Catalog_Parts1`
    FOREIGN KEY (`pid` )
    REFERENCES `mydb`.`Parts` (`pid` )
    ON DELETE NO ACTION
    ON UPDATE NO ACTION,
  CONSTRAINT `fk_Catalog_Suppliers1`
    FOREIGN KEY (`sid` )
    REFERENCES `mydb`.`Suppliers` (`sid` )
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB;



SET SQL_MODE=@OLD_SQL_MODE;
SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS;
SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS;

Answer 1

不知道你在做什么我发现有些事情是错的.首先删除子查询中的第二列,这是不必要的:

SELECT Parts.color 
FROM Suppliers, Catalog, Parts 
WHERE Suppliers.sid NOT IN (     
    SELECT Suppliers.sid    FROM Suppliers, Catalog, Parts 
    WHERE Suppliers.sid = Catalog.sid  
        AND Catalog.pid = Parts.pid 
        AND (Parts.color = "red" OR Parts.color = "green") 
    ); 

最后你有一个我认为你不想要的交叉连接.这是为什么不应该使用隐式连接的典型示例.看看这可能会更好:

SELECT Parts.color 
FROM Suppliers 
JOIN Catalog  on Suppliers.sid = Catalog.sid  
JOIN  Parts on Catalog.pid = Parts.pid 
WHERE Suppliers.sid NOT IN (     
    SELECT Suppliers.sid
    FROM  Suppliers 
    JOIN Catalog  on Suppliers.sid = Catalog.sid  
    JOIN  Parts on Catalog.pid = Parts.pid 
       WHERE (Parts.color = "red" OR Parts.color = "green") 
    );