Yun*_*ium 5 php ajax jquery laravel-4
我试图从中选择选项<select>,将其传递给show()控制器中的方法,使用它从数据库中检索数据,然后将其作为json返回到成功方法中$.ajax.所有这一切都在发生jquery.ajax.
如何从$.ajax请求传递数据来获取/接收数据?
这是我正在使用的代码:
Route::post('rate/units',array('as'=>'unitRoute','uses'=>'RateController@show'));
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public function show()
{
$row[] = $_POST['deg'];
return json_encode($row);
}
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<select class="form-control choosedegree" name="sem" id="semester">
<option value="" selected="selected" disabled>Select Semester</option>
<option value="1">Year 1, Semester 1</option>
<option value="2">Year 1, Semester 2</option>
<option value="3">Year 2, Semester 1</option>
<option value="4">Year 2, Semester 2</option>
<option value="5">Year 3, Semester 1</option>
<option value="6">Year 3, Semester 2</option>
<option value="7">Year 4, Semester 1</option>
<option value="8">Year 4, Semester 2</option>
</select>
<script>
$(document).ready(function() {
$('select#semester').on('change', function() {
var optionSelected = $(this).find("option:selected");
semesterSelected = optionSelected.val();
console.log(semesterSelected);
$.ajax({
type: "POST",
cache: false,
url : "rate/units",
data: { sem : semesterSelected },
success: function(data) {
var obj = $.parseJSON(data);
var i = 0;
console.log(data.iyo);
$.each(obj, function() {
console.log(this[0]);
console.log(this[1]);
console.log(this[2]);
console.log(this[3]);
console.log(this[4]);
i++;
});
}
})
.done(function(data) {
alert('done');
})
.fail(function(jqXHR, ajaxOptions, thrownError) {
alert('No response from server');
});
});
});
</script>
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Ant*_*iro 11
您可以使用输入检索发布数据:
public function show()
{
$semester = Input::get('sem');
return json_encode($semester);
}
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要调试它,您可以:
public function show()
{
Log::info(Input::all());
$semester = Input::get('sem');
return json_encode($semester);
}
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然后在控制台执行
php artisan tail
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