在PHP中简化数组

Question

我有以下需要在PHP中定义的数组,我已经以非常基本的方式完成了:

$ch1 = array("A-MTP-1-1","A-MTP-1-2","A-MTP-1-3","A-MTP-1-4"); 
$ch2 = array("A-MTP-1-5","A-MTP-1-6","A-MTP-1-7","A-MTP-1-8"); 
$ch3 = array("A-MTP-1-9","A-MTP-1-10","A-MTP-1-11","A-MTP-1-12");

$ch4 = array("A-MTP-2-1","A-MTP-2-2","A-MTP-2-3","A-MTP-2-4"); 
$ch5 = array("A-MTP-2-5","A-MTP-2-6","A-MTP-2-7","A-MTP-2-8"); 
$ch6 = array("A-MTP-2-9","A-MTP-2-10","A-MTP-2-11","A-MTP-2-12");

$ch7 = array("A-MTP-3-1","A-MTP-3-2","A-MTP-3-3","A-MTP-3-4"); 
$ch8 = array("A-MTP-3-5","A-MTP-3-6","A-MTP-3-7","A-MTP-3-8"); 
$ch9 = array("A-MTP-3-9","A-MTP-3-10","A-MTP-3-11","A-MTP-3-12");

但我认为必须有一个简单的方法来编写这个,而不是写出每个但不知道从哪里开始,是否有人能够指出我正确的方向来简化这个PHP,因为我也将重复它为以上,但每个都用B而不是A.

Answer 1

使用range(),array_chunk并extract完成这项工作

<?php

for ($i = 1; $i <= 3; $i++) {           # Pass 3 as you need three sets
    foreach (range(1, 12) as $val) {    # 1,12 again as per your requirements
        $arr[] = "A-MTP-$i-" . $val;

    }
}
foreach (array_chunk($arr, 4) as $k => $arr1) {    # Loop the array chunks and set a key
    $finarray["ch" . ($k + 1)] = $arr1;
}
extract($finarray);   # Use the extract on that array so you can access each array separately
print_r($ch9);        # For printing the $ch9 as you requested.

Demo

OUTPUT :($ch9仅为部分图示)

Array
(
    [0] => A-MTP-3-9
    [1] => A-MTP-3-10
    [2] => A-MTP-3-11
    [3] => A-MTP-3-12
)

执行此操作后,您可以使用array_chunk将数组拆分为4的长度.