使用EPPlus的Excel日期格式

Question

我将格式化单元格设置为日期时遇到问题.

FileInfo info = new FileInfo(path);
using (ExcelPackage package = new ExcelPackage(info))
{
      ExcelWorksheet ws = package.Workbook.Worksheets.Add(sheetName);
      ws.Cells[3, 1].Style.Numberformat.Format = "yyyy-mm-dd";
      ws.Cells["A3"].Formula = "=DATE(2014,10,5)";
}

在Excel中输出:41 917,00

为什么这不起作用？

Answer 1

我同意Yosoyke.你可能是针对错误的细胞.你可以试试:

ws.Cells["A3"].Style.Numberformat.Format = "yyyy-mm-dd";
ws.Cells["A3"].Formula = "=DATE(2014,10,5)";

Answer 2

worksheet.Cells["YOURDATECELL_OR_YOURDATECELLRANGE"].Style.Numberformat.Format = "mm-dd-yy";

如果你使用taraz提到的公式.最后添加workheet.Calculate().参考 https://epplus.codeplex.com/wikipage?title=About%20Formula%20计算

或者不使用公式,替代方法

private static decimal GetExcelDecimalValueForDate(DateTime date)
{
    DateTime start = new DateTime(1900, 1, 1);
    TimeSpan diff = date - start;
    return diff.Days + 2;
}

参考

worksheet.Cells["A2"].Value = GetExcelDecimalValueForDate(Convert.ToDateTime('2016-04-29'));
worksheet.Cells["A2"].Style.Numberformat.Format = "mm-dd-yy";//or m/d/yy h:mm

默认情况下,当excel保存日期字段时,它将其保存为numFormatId14(查看xls中的xml文件).这样可确保在打开文件时在任何国家/地区正确格式化日期.在Epplus中,excel的mm-dd-yy翻译为numFormatId14.这将确保在任何国家/地区打开文件时,将根据国家/地区的短日期设置正确格式化日期.还注意到m/d/yy h:mm任何国家的格式正确.

Answer 3

var dateColumns = from DataColumn d in dt.Columns
                  where d.DataType == typeof(DateTime) || d.ColumnName.Contains("Date")
                  select d.Ordinal + 1;

foreach (var dc in dateColumns)
{
    worksheet.Cells[2, dc, rowCount + 2, dc].Style.Numberformat.Format = "mm/dd/yyyy hh:mm:ss AM/PM";
}

它将所有带有标题Date的列格式化为给定/提供的特定格式

Answer 4

通用解决方案采用 IEnumerable （数据），循环遍历通用对象的属性，查找 DateType 或 nullableDate 类型并应用格式设置：

   //set the list of dateColumns which will be used to formate them
            List<int> dateColumns = new List<int>();

            //get the first indexer
            int datecolumn = 1;

            //loop through the object and get the list of datecolumns
            foreach (var PropertyInfo in data.FirstOrDefault().GetType().GetProperties())
            {
                //check if property is of DateTime type or nullable DateTime type
                if (PropertyInfo.PropertyType == typeof(DateTime) || PropertyInfo.PropertyType == typeof(DateTime?))
                {
                    dateColumns.Add(datecolumn);
                }
                datecolumn++;
            }

            // Create the file using the FileInfo object
            var file = new FileInfo(outputDir + fileName);

            //create new excel package and save it
            using (var package = new ExcelPackage())
            {
                //create new worksheet
                var worksheet = package.Workbook.Worksheets.Add("Results");


                // add headers
                worksheet.Cells["A1"].LoadFromCollection(data, true);

                //format date field 
                dateColumns.ForEach(item => worksheet.Column(item).Style.Numberformat.Format = "dd-mm-yyyy");

                // auto size columns
                worksheet.Cells.AutoFitColumns();

                //save package
                package.SaveAs(file);
            }

Answer 5

我在转换 CSV 时遇到了同样的问题。我能够以稍微不同的方式做到这一点。

private string ConvertToExcel(string CSVpath, string EXCELPath)
    {
        try
        {
            string Filename = System.IO.Path.GetFileNameWithoutExtension(CSVpath);
            string DirectoryName = System.IO.Path.GetDirectoryName(CSVpath);
            EXCELPath = DirectoryName + "\\" + Filename + ".xlsx";

            string worksheetsName = "Report";
            bool firstRowIsHeader = false;

            var format = new OfficeOpenXml.ExcelTextFormat();
            format.Delimiter = '|';
            format.EOL = "\n";

            using (OfficeOpenXml.ExcelPackage package = new OfficeOpenXml.ExcelPackage(new System.IO.FileInfo(EXCELPath)))
            {
                string dateformat = "m/d/yy h:mm";
                //string dateformat = System.Globalization.DateTimeFormatInfo.CurrentInfo.ShortDatePattern;

                OfficeOpenXml.ExcelWorksheet worksheet = package.Workbook.Worksheets.Add(worksheetsName);
                worksheet.Cells["A1"].LoadFromText(new System.IO.FileInfo(CSVpath), format, OfficeOpenXml.Table.TableStyles.Medium2, firstRowIsHeader);

                worksheet.Column(3).Style.Numberformat.Format = dateformat;
                worksheet.Column(5).Style.Numberformat.Format = dateformat;
                worksheet.Column(6).Style.Numberformat.Format = dateformat;
                worksheet.Column(20).Style.Numberformat.Format = dateformat;
                worksheet.Column(21).Style.Numberformat.Format = dateformat;
                worksheet.Column(22).Style.Numberformat.Format = dateformat;




                package.Save();
            }
        }
        catch (Exception ex)
        {
            //DAL.Operations.Logger.LogError(ex);
            Console.WriteLine(ex);
            Console.Read();
        }
        return EXCELPath;
    }