Ale*_*lex 4 asp.net selectedindexchanged code-behind drop-down-menu
我在代码隐藏中生成一个下拉列表,无法自动触发selectedindexchanged事件.它直接放入ASPX页面时工作正常,但我需要它在代码隐藏中.
这不起作用:
var deptList = new DropDownList
{
ID = "deptList",
DataSource = departments,
DataTextField = "deptname",
DataValueField = "deptid",
AutoPostBack = true,
EnableViewState = true
};
deptList.SelectedIndexChanged += new EventHandler(deptList_SelectedIndexChanged);
deptList.DataSource = departments;
deptList.DataTextField = "deptname";
deptList.DataValueField = "deptid";
if (!IsPostBack)
deptList.DataBind();
deptList.Items.Insert(0, new ListItem("---Select Department---", string.Empty));
writer.Write("Select a department: ");
deptList.RenderControl(writer);
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但这有效:
<asp:DropDownList ID="deptList" AutoPostBack="true" runat="server" OnSelectedIndexChanged="deptList_SelectedIndexChanged"></asp:DropDownList>
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问题可能在于您没有及早将控件添加到页面.需要在页面生命周期的早期添加控件以使其事件处于捆绑状态.
您可能在Load事件中执行此操作,为时已晚.尝试在Init事件期间添加它或覆盖CreateChildControls方法.
编辑:正如Dave Swersky所提到的,请确保在每个页面请求(包括回发)上执行此操作.
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